Answer:
BET
Step-by-step explanation:
70, GIVE ME BRAINLIESt
Answer:
f'(x) = ![-\frac{9}{x^2}](https://tex.z-dn.net/?f=-%5Cfrac%7B9%7D%7Bx%5E2%7D)
Step-by-step explanation:
i) f(x) = 9 / x
ii) f'(x) = ![$\lim_{h\to 0} \frac{f(x+h) - f(x)}{h} $ \hspace{0.2cm}](https://tex.z-dn.net/?f=%24%5Clim_%7Bh%5Cto%200%7D%20%5Cfrac%7Bf%28x%2Bh%29%20-%20f%28x%29%7D%7Bh%7D%20%24%20%20%5Chspace%7B0.2cm%7D)
![= $\lim_{h\to 0} \frac{\frac{9}{x+h} - \frac{9}{x} }{h} = \hspace{0.1cm} $\lim_{h\to 0} \frac{9x - 9(x+h)}{hx(x+h)} $ \hspace{0.1cm} = \hspace{0.1cm}$\lim_{h\to 0} \frac{-9h}{hx(x+h)} = $\lim_{h\to 0} \frac{-h}{x(x+h)} = \frac{-9}{x^2}$](https://tex.z-dn.net/?f=%3D%20%24%5Clim_%7Bh%5Cto%200%7D%20%5Cfrac%7B%5Cfrac%7B9%7D%7Bx%2Bh%7D%20%20-%20%5Cfrac%7B9%7D%7Bx%7D%20%7D%7Bh%7D%20%20%3D%20%20%5Chspace%7B0.1cm%7D%20%24%5Clim_%7Bh%5Cto%200%7D%20%5Cfrac%7B9x%20-%209%28x%2Bh%29%7D%7Bhx%28x%2Bh%29%7D%20%24%20%5Chspace%7B0.1cm%7D%20%3D%20%20%5Chspace%7B0.1cm%7D%24%5Clim_%7Bh%5Cto%200%7D%20%5Cfrac%7B-9h%7D%7Bhx%28x%2Bh%29%7D%20%20%3D%20%20%24%5Clim_%7Bh%5Cto%200%7D%20%5Cfrac%7B-h%7D%7Bx%28x%2Bh%29%7D%20%3D%20%5Cfrac%7B-9%7D%7Bx%5E2%7D%24)
The answer to your question is a 16-gon
Let <em>x</em> = 8.132132132... .
Then 1000<em>x</em> = 8132.132132132... .
Subtracting <em>x</em> from 1000<em>x</em> eliminates the fractional part, leaving you
999<em>x</em> = 8132 - 8 = 8124
Then
<em>x</em> = 8124/999 = 2708/333
Answer:
1/2 and 1
Step-by-step explanation:
1 is equal to 1 so it is less than and equal to and 1/2 because as a decimal form it is .5 which is 50% which is less 1 as a percentage, 100%.
Sorry this is late, but I hope it helps others! By the way, I did this and got it correct on Khan Academy.