195/6 = 32.5 so it is $32.50
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Answer:


Step-by-step explanation:
Given;
(a) y = tan(5t)

Solving for (a)
y = tan(5t)
let u = 5t
⇒y = tan(u)
du/dt = 5
dy/du = sec²u


Solving for b;
let u = 5 - v²
du/dv = -2v
let v = 5+ v²
dv/du = 2v


First off, we factor out the expression:

In the bracket, separate 8 out of the expression.
![\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 8)] }\\ \displaystyle \large{y = 2[ ( {x}^{2} - 6x) + 8]}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%28%20%7Bx%7D%5E%7B2%7D%20-%206x%20%2B%208%29%5D%20%7D%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%28%20%7Bx%7D%5E%7B2%7D%20-%206x%29%20%2B%208%5D%7D)
In x^2-6x, find the third term that can make up or convert it to a perfect square form. The third term is 9 because:

So we add +9 in x^2-6x.
![\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 9) + 8]}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%28%20%7Bx%7D%5E%7B2%7D%20-%206x%20%2B%209%29%20%20%2B%208%5D%7D)
Convert the expression in the small bracket to perfect square.
![\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8]}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20%2B%208%5D%7D)
Since we add +9 in the small bracket, we have to subtract 8 with 9 as well.
![\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8 - 9]} \\ \displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20%2B%208%20-%209%5D%7D%20%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20-%201%5D%7D)
Then we distribute 2 in.
![\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20-%201%5D%7D%20%5C%5C%20)
![\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\ \displaystyle \large{y = [2 \times {(x - 3)}^{2} ]+[ 2 \times ( - 1)] } \\ \displaystyle \large{y = 2 {(x - 3)}^{2} - 2 }](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20-%201%5D%7D%20%5C%5C%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%20%5B2%20%5Ctimes%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%5D%2B%5B%202%20%5Ctimes%20%28%20-%201%29%5D%20%7D%20%5C%5C%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20-%202%20%7D)
Remember that negative multiply positive = negative.
Hence the vertex form is y = 2(x-3)^2-2 or first choice.
Answer: 2.625
Step-by-step explanation:
All you have to do is divide 5 by 8 which gives you .625 and then you put the 2 in front of the decimal amd you get your answer.
<span>If m = the weight of boxes that marco lifted, and each box that drew lifted was 8 lbs less than marcos boxes, then you would multiply the total number of boxes that drew lifted by the weight of marcos total boxes - 8
or 14(m-8)</span>