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2 years ago

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Dasher spent half as much as prancer did on holiday presents this year and cupid spent 3 times more than dasher. If the total sp

ent between the three of them was $720, how much did they each spend on gifts?

1 answer:

Dmitrij [34]2 years ago

6 0

Answer:

Dasher spent $120, Prancer spent $240, and Cupid spent $360

Step-by-step explanation:

Divide 720 by 2 and you get 360, which was cupids total. There is 360 left. Subtract 360 by 240 because Dasher spent half as much as prancer did. You get 120, which is Dasher's total. The 240 you subtracted is Prancer's total.

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Calculate the arithmetic sequence in which a9=17 and the common difference is d=-2.1

jek_recluse [69]

Answer:

$S_{31}=71.3$

Step-by-step explanation:

The nth term of an arithmetic sequence is given by the formula,

$U_n=a_1+(n-1)d$

We were given that the 9th term is $17$ .

$\Rightarrow 17=a_1+(9-1)(-2.1)$

$\Rightarrow 17=a_1+(8)\times(-2.1)$

$\Rightarrow 17=a_1-\frac{84}{5}$

$\Rightarrow 17+\frac{84}{5}=a_1$

$\Rightarrow a_1=\frac{169}{5}$

The sum of the first n-terms is given by the formula,

$S_n=\frac{n}{2}(2a_1+(n-1)d)$

To find $S_{31}$ , we substitute $n=31$ , $a_1=\frac{169}{5}$ and $d=-2.1$ .

$\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(31-1)(-2.1))$

$\Rightarrow S_{31}=\frac{31}{2}(2(\frac{169}{5}+(30)(-2.1))$

$\Rightarrow S_{31}=\frac{31}{2}(\frac{23}{5})$

$\Rightarrow S_{31}=\frac{713}{10}$

$\Rightarrow S_{31}=71.3$

The correct answer is D

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3 years ago

Read 2 more answers

Work out 25% of £18

konstantin123 [22]

It’s £4.5

Convert 25 to a decimal so 0.25

0.25 x 18 = 4.5

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2 years ago

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B) Find g (-3) for g(x) = 3x + 5

fredd [130]

Step-by-step explanation:

g(x)=3x+5

g(-3)=3(-3)+5

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2 years ago

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EleoNora [17]

Answer:

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Step-by-step explanation:

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$\frac{1}{4}=\frac{2}{8}$

Now, we can't subtract 2 from 8, so we need to 'borrow' from the 6 to make the fraction larger:

$6\frac{2}{8}=5\frac{10}{8}$

Now subtract: $5\frac{10}{8}-1\frac{5}{8}=4\frac{5}{8}$

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