3 years ago

Explain the question and I'll add you as branlist

Mathematics

2 answers:

Ilya [14]3 years ago

8 0

Answer:

What question? We need more context

ZanzabumX [31]3 years ago

4 0

Answer:

The question is a question that is asked by someone who is asking a question, to whom they most likely need an answer to

Step-by-step explanation:

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Which of the following fractions have the same value as 16 ÷ (–3)? Check all that apply.

Snowcat [4.5K]

Answer:

StartFraction 16 over negative 3, EndFraction StartFraction negative 16 over 3, and EndFraction Negative (StartFraction 16 over 3 EndFraction)

I hope this helps

Step-by-step explanation:

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2 years ago

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PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!

Semenov [28]

Answer:

1/20

Alternate from 0.05, 20 - 1

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3 years ago

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The Junior Beta club needs to raise $1513.75 to go to a national convention. If they decided to sell candy bars at $1.25 each, h

rusak2 [61]

Answer:

1,211 candy bars.

Step-by-step explanation:

You divide the goal by how much the bars are selling for, or 1513.75/1.25. The answer to this is 1,211 candy bars.

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3 years ago

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Which equation can be used to find the measure of Arc E H G?

anygoal [31]

Answer:

I need more context ,like the graph to figure this out.

Step-by-step explanation:

5 0

2 years ago

Use Laplace transform methods to solve the differential equation: The initial conditions are f(0) = 0 and <img src="https://tex.

Llana [10]

Answer:

Step-by-step explanation:

$\frac{d^2 y}{dt^2} +12\frac{dy}{dt} +32y = 10e^{-2t}$ where f(x) is replaced by y

Take Laplace on both sides

$s^2 Y -s(0)-0 +12s Y-0+32Y = \frac{10}{s+2} \\Y(s^2+12s+32) = \frac{10}{s+2}\\Y = \frac{10}{(s+2)(s+4)(s+8)}$

We can resolve into partial fraction to get Y = L(y)

Let this equals

$\frac{A}{s+2} +\frac{B}{s+4} +\frac{C}{s+8} \\10 = A(s+4)(s+8) + B(s+2)(s+8) +Cs+4)(s+2) \\$

Solving we get

s=-9

24C = 10 or C =5/12

s=-2: A=10/12=5/6

s=-4: B = -5/4

Taking inverse Laplace

$y(t) = \frac{-5e^{-4t} }{4} + \frac{5e^{-8t} }{12} +\frac{-5e^{-2t} }{6}$

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3 years ago