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lawyer [7]
3 years ago
8

Explain the question and I'll add you as branlist

Mathematics
2 answers:
Ilya [14]3 years ago
8 0

Answer:

What question? We need more context

ZanzabumX [31]3 years ago
4 0

Answer:

The question is a question that is asked by someone who is asking a question, to whom they most likely need an answer to

Step-by-step explanation:

You might be interested in
Mrs. Roberson has 5 more students in her class than Mr. Monroe. Together, they have 57 students. Write an equation that can be u
Ivahew [28]

Answer:

Step-by-step explanation:

the basic number will be represented by X so, the equation will be

Mr. Monroe Mrs. Roberson

X X+5

57 = X + (X+5)

8 0
3 years ago
How do I solve this problem (5.21 x 10^-5)^2
iragen [17]
(5.21\cdot10^{-5})^2=5.21^2\cdot(10^{-5})^2=27.1441\cdot10^{-10}=2.71441\cdot10^{-9}
8 0
4 years ago
What is the equation in point-slope form of the line that passes through (-9, 12) with a slope of 5/6?​
Hitman42 [59]

Answer:

\large\boxed{y-12=\dfrac{5}{6}(x+9)}

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - point on a line</em>

<em />

We have

m=\dfrac{5}{6},\ (-9,\ 12)\to x_1=-9,\ y_1=12

Substitute:

y-12=\dfrac{5}{6}(x-(-9))\\\\y-12=\dfrac{5}{6}(x+9)

6 0
3 years ago
Someone help me please
RoseWind [281]

9514 1404 393

Answer:

  • A = (0, 1)
  • B = (3, -2)
  • area = 4.5 square units

Step-by-step explanation:

Rewriting the equations to make x the subject, we have ...

  x = y² -1 . . . . . [eq1]

  x = 1 - y . . . . . .[eq2]

At the points of intersection, the difference will be zero.

  y² -1 -(1 -y) = 0

  y² +y -2 = 0

  (y -1)(y +2) = 0

The y-coordinates of points A and B are 1 and -2.

The corresponding x-coordinates are ...

  x = 1 -{1, -2} = {1 -1, 1+2} = {0, 3}

Then A = (0, 1) and B = (3, -2).

__

A differential of area can be written ...

  (x2 -x1)dy = ((1 -y) -(y² -1))dy = (2 -y -y²)dy

Integrating this over the interval y = [-2, 1] gives the area.

  \displaystyle A=\int_{-2}^1(2-y-y^2)\,dy=\left.(2y-\dfrac{1}{2}y^2-\dfrac{1}{3}y^3)\right|_{-2}^1\\\\=\left(2-\dfrac{1}{2}-\dfrac{1}{3}\right)-\left(2(-2)-\dfrac{(-2)^2}{2}-\dfrac{(-2)^3}{3}\right)=\dfrac{7}{6}+4+2-\dfrac{8}{3}\\\\=\boxed{4.5}

The area of the shaded region is 4.5 square units.

5 0
3 years ago
Are the ratios 1:20 and 2:4 equivalent?
Lisa [10]

Answer:

no

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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