Hey guys pls help help me Find the Area of the Rhombus

Mathematics

1 answer:

Hatshy [7]2 years ago

7 0

Answer:

210 m²

Step-by-step explanation:

The area of a rhombus is d₁ * d₂ * 0.5. In other words, the area is its diagonals multiplied together and divided by 2.

Substitute the measures of the diagonal given.

35 * 12 * 0.5 = 210

The area is 210 m²

I hope this helps! Feel free to ask any questions!

Why is (D₁ + D₂)/2 incorrect?

This is a really helpful link:

http://mathandmultimedia.com/2015/03/04/why-the-area-of-a-rhombus-half-the-product-of-its-diagonals/

https://byjus.com/maths/area-of-rhombus/

You might be interested in

20. A ball is dropped from a height of a little over 5 feet, and the height is measured at small intervals. The table below show

nekit [7.7K]

Step 1:

a) Write the quadratic model

a = -15.64

b = -1.24

c = 5.23

$P(t)=-15.64t^2\text{ - 1.24t + 5.2}3$

b) t = 0.30

$\begin{gathered} P(t)=-15.64t^2\text{ - 1.24t + 5.2}3 \\ =\text{ -15.64 }\times0.3^2\text{ - 1.24}\times\text{ 0.3 + 5.2}3 \\ =\text{ -1.4076 - 0.372 + }5.23 \\ =\text{ 3.45} \end{gathered}$

c) t = 0.52 seconds

$\begin{gathered} p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ =\text{ -15.64}\times0.52^2\text{ - 1.23}\times0.52\text{ + 5.23} \\ =\text{ -4.23 - 0.64 + 5.23} \\ =\text{ 0.36} \end{gathered}$

d) 0.30 is more likely to be relaible.

$\begin{gathered} p(t)\text{ = 1} \\ p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ 1=-15.64t^2\text{ - 1.23t + 5.23} \\ -15.64t^2\text{ - 1.23t + 4.23 = 0} \\ t\text{ = 0.48222} \\ \text{t = 0.48 seconds} \end{gathered}$

5 0

9 months ago

A spieces of extremely rare, deep water fish are slowly becoming extinct. If there are a total of 821 of this type of fish and t

Step2247 [10]

Answer:

12 months in a year

6 is half a month so we're going off of 6 months.

So:

821*0.15= 123.15

821- 123.15= 697.85

697.85*0.15= 104.6775

697.85-104.6775= 593.1725