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2 years ago

I JUST NEED HELP PLZZ AND THANK YOU

Mathematics

1 answer:

Kamila [148]2 years ago

6 0

Answer:

Step-by-step explanation:

Based on the pattern of the scatter plot, 43 seems to be the better option.

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How to solve this problem

PolarNik [594]

X- 6/4=7
x-6=7×4
x-6=28
x=28-6
x=22

4 0

3 years ago

HELP!!!

Bad White [126]

I hope this helps you

-15+6= -9

-9+6= -3

-3+6=3

add 6

3 0

3 years ago

Read 2 more answers

I need help understanding square roots

Vlad [161]

I wonder if you mean to write $\sqrt[3]{256}$ in place of $3\sqrt{256}$ ...

If you meant what you wrote, then we have

$\sqrt{256}=\sqrt{16^2}=16$

$3\sqrt{256}=3\cdot16=48$

If you meant to write $\sqrt[3]{256}$ (the cube root of 256), then we could go on to have

$\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4$

6 0

3 years ago

The length of a rectangle is 4 centimeters more than twice its width of the perimeter of the rectangle is 86centimeters find the

lana66690 [7]

Answer:

$Width= 13 cm$

$length=30cm$

Step-by-step explanation:

Let the length of the rectangle be 'L'

And the width of the rectangle be 'W'

$Perimeter= 86 cm$

According to the statement:

$Length= 2*Width+4\\L=2W+4$

Perimeter of a rectangle= 2(Length+Width)

$86=2(2W+4+W)\\86/2=3W+4\\43=3W+4\\3W=43-4\\3W=39\\W=39/3\\W=13 cm\\\\Length(L)=2W+4\\=2(13)+4=26+4=30 cm\\Length=30 cm$

$Width= 13 cm$

$length=30cm$

6 0

2 years ago

If NTM is congruent to OUM, SP is congruent to SQ, S is the center of the circle, and OM = 18, find NT. Round the answer to the

Aleks [24]

OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13

4 0

2 years ago