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sveta [45]
3 years ago
5

A ball at the end of a 2 meter string revolves in a circle at a rate of 4 m/s. What

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Answer:

8 m/s^2

Step-by-step explanation:

You can use the equation a = v^2 / r

That is acceleration is equal to velocity squared divided by the radius which in this problem is the length of the string. The velocity is 4m/s and the r the radius is 2 m. Now you can square 4 m/s to get 16 m^2/s^2 THEN you divide by 2 m and the m^2 turns to just m and the 16 to an 8. So, that leaves you with acceleration or in this case centripetal acceleration equals 8 m/s^2.

a = 8 m/s^2     or  8 meters per second squared.

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I’ll mark you brainliest!!!!! Which point is a solution to the inequality represented by this graph?
Setler [38]

Answer:

A is a solution because it is in the shaded area.

Step-by-step explanation:

4 0
4 years ago
Use digits to write each number. 5. Twelve thousand, three hundred forty-five 6. Fifty-three million, eighty-nine thousand, seve
postnew [5]

Answer:

5. Twelve thousand, three hundred forty-five can be written as 12,345.

6. Fifty-three million, eighty-nine thousand, seven hundred two can be written as 53,089,702.

7. Two hundred fifty-six thousand, seven hundred eighty can be written as 256,780.

8. Eighty-five thousand, nine can be written as 85,009.

9. Two hundred thirty-eight thousand, eight hundred fifty-seven miles can be written as 238,857.

Step-by-step explanation:

According to the place value chart:

Millions     Hundred Th. Ten Th     Thousands   hundreds   Tens   Ones

1,000,000    100,000       10,000       1,000             100            10        1

We can write any number with the help of place value chart:

For example:

8 thousand, seven hundred seventy-five.

8,000+700+75 = 8,775

Now consider the provided information.

5. Twelve thousand, three hundred forty-five

This can be written as:

12,000+300+45 = 12,345

Twelve thousand, three hundred forty-five can be written as 12,345.

6. Fifty-three million, eighty-nine thousand, seven hundred two

This can be written as:

53,000,000+89,000+700+2 = 53,089,702

Fifty-three million, eighty-nine thousand, seven hundred two can be written as 53,089,702.

7. Two hundred fifty-six thousand, seven hundred eighty

This can be written as:

256,000+780 = 256,780

Two hundred fifty-six thousand, seven hundred eighty can be written as 256,780.

8. Eighty-five thousand, nine

This can be written as:

85,000+9 = 85,009

Eighty-five thousand, nine can be written as 85,009.

9. Two hundred thirty-eight thousand, eight hundred fifty-seven miles

This can be written as:

238,000+800+57 = 238,857

Two hundred thirty-eight thousand, eight hundred fifty-seven miles can be written as 238,857.

8 0
3 years ago
Line segment AB has endpoints A(−1,6) and B(5,−6).
k0ka [10]

Answer:

(0,4)

it was correct

4 0
3 years ago
What is the equation in standard form
jeka94

Answer:

7y = 20

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can someone help me it’s due today
Marizza181 [45]

Answer:

C

Step-by-step explanation:

So if x is the number, then 4 times the number would be 4x and adding that to -8 would be 4x + (-8) and then 12 times the number would be 12x, so you have 4x + (-8) = 12.

Then, solve:

4x - 8 = 12x\\

subtract 4x from both sides

-8 = 8x

divide both sides by 8

-1 = x \\x = -1

6 0
3 years ago
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