
Actually Welcome to the Concept of the Functions.
So here to get the (f-g) (x) , we do the subtraction of the two functions now,
==> 8x + 5 - (9x -2)
===> 8x + 5 -9x +2
===> 8x - 9x +7
==> -x + 7
hence the new function (f-g) (x) = 7 - x
and the domain is from (- infinite to + infinite)

Zero<span> Celsius is </span>freezing<span> temperature. It would melt if it were higher than </span>zero<span>.</span>
Answer:
(5,19) lies on the graph of the transformed function y = f(1/5x)
Step-by-step explanation:
Suppose (1,19) is on the graph of y = f (x)
the graph of the transformed function y = f(1/5x)

1/5 is multiplied with x in f(x)
1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5
To make horizontal stretch we change the point
f(x)=f(bx) then (x,y) --->( x/b,y)
We divide the x coordinate by the fraction 1/5
(1,19) ----> 
So (5,19) lies on the graph of the transformed function y = f(1/5x)
Since 2 and 11 are prime we have
(2x 1)(1x 11) or
(2x 11)(1x 1)
we just need to figure out the signs
remember
(ax+b)(cx+d)=acx^2+bcx+adx+bd
the middle term coeficient is bc+ad
so
2x times 11=22x
1x times 1=x
there is not way to add or subtract 22x and x to get -9x
1st one is wrong
(2x 11)(x 1)
2x times 1=2x
11 times x=11x
11x-2x=9x
the 2x or the 1 has to have the negative
(2x+11)(x-1)