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hichkok12 [17]
3 years ago
7

What is the square root of 5690

Mathematics
2 answers:
Dafna11 [192]3 years ago
6 0
The satire root of 5690 is 75.4320886626
Lera25 [3.4K]3 years ago
4 0
75.432088626 is the square root of 5690
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Let f(x)=8x+5 and g(x)=9x-2. find the function.<br>f - g<br>(f - g) (x) =<br>find the domain.​
Rom4ik [11]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Functions.

So here to get the (f-g) (x) , we do the subtraction of the two functions now,

==> 8x + 5 - (9x -2)

===> 8x + 5 -9x +2

===> 8x - 9x +7

==> -x + 7

hence the new function (f-g) (x) = 7 - x

and the domain is from (- infinite to + infinite)

domain = (  -  \infty  \: to \:  \infty )

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3 years ago
Why must ice cream be cooled below 0 before is freezes?
djverab [1.8K]
Zero<span> Celsius is </span>freezing<span> temperature. It would melt if it were higher than </span>zero<span>.</span>
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3 years ago
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Suppose (1,19) is on the graph of y = f (x). Which of the following points lies on the graph of the transformed function y = f(1
o-na [289]

Answer:

(5,19) lies on the graph of the transformed function y = f(1/5x)

Step-by-step explanation:

Suppose (1,19) is on the graph of y = f (x)

the graph of the transformed function y = f(1/5x)

y=f(\frac{1}{5}x)

1/5 is multiplied with x  in f(x)

1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5

To make horizontal stretch we change the point

f(x)=f(bx) then (x,y) --->( x/b,y)

We divide the x coordinate by the fraction 1/5

(1,19) ----> (\frac{1}{\frac{1}{5}} , 19)= (5,19)

So (5,19) lies on the graph of the transformed function y = f(1/5x)

8 0
4 years ago
a store buys a jacket for $20.00 and then sells it to costumers for 80% more than that.What is the selling price of the jacket?
Harlamova29_29 [7]

Answer:

$36

Step-by-step explanation:

20+80%=36

5 0
4 years ago
Factor 2x2 - 9x - 11.
tester [92]
Since 2 and 11 are prime we have
(2x 1)(1x 11) or
(2x 11)(1x 1)
we just need to figure out the signs

remember
(ax+b)(cx+d)=acx^2+bcx+adx+bd
the middle term coeficient is bc+ad
so
2x times 11=22x
1x times 1=x
there is not way to add or subtract 22x and x to get -9x

1st one is wrong

(2x 11)(x 1)

2x times  1=2x
11 times x=11x
11x-2x=9x

the 2x or the 1 has to  have the negative

(2x+11)(x-1)
6 0
4 years ago
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