The answer to your question would be 654
If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
8ft = 2yrds and 2 feet
68in= 5ft and 8in
I don't know the last one XD
4 + 3 + 2 = 9
18/9 = 2
3 x 2 = 6
Answer = 6
