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pychu [463]
3 years ago
15

HELP ME PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer: are you supposed to add them?

Step-by-step explanation:

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A rectangle is drawn on a coordinate plane and has vertices at ( − 4, 9), (5, 9), (5, − 2), and ( − 4, − 2). How many units long
r-ruslan [8.4K]

Answer:

60 square units ✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨✨

5 0
4 years ago
Solve and express the solution set in simplest form.
oee [108]

Answer:

\frac{11}{6}

Step-by-step explanation:

The equation to be solve is

4x−1/3=7/1

We can go about this by first adding 1/3 to both sides.

4x -  \frac{1}{3}  + \frac{1}{3} = \frac{7}{1} +  \frac{1}{3}

\implies \ 4x = \frac{7}{1} +  \frac{1}{3}

We then simplify the the right hand side of the equation

\implies 4x =  \frac{21 + 1}{3}

\implies 4x =  \frac{22}{3}

To find x, we multiply through by 1/4

\implies  \frac{1}{4}  \times 4x = \frac{22}{3} \times  \frac{1}{4}

\implies x = \frac{22}{12}

\implies x = \frac{11}{6}

Hence the solution set in the simplest form for the expression is

{x=11/2}

6 0
3 years ago
State the number of possible triangles that can be formed using the given measurements.
romanna [79]

Answer:  39) 1              40) 2

                41) 1              42) 0

<u>Step-by-step explanation:</u>

39)     ∠A = ?        ∠B = ?       ∠C = 129°

            a = ?          b = 15         c = 45

Use Law of Sines to find ∠B:

\dfrac{\sin B}{b}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin B}{15}=\dfrac{\sin 129}{45}\rightarrow \quad \angle B=15^o\quad or \quad \angle B=165^o

If ∠B = 15°, then ∠A = 180° - (15° + 129°) = 36°

If ∠B = 165°, then ∠A = 180° - (165° + 129°) = -114°

Since ∠A cannot be negative then ∠B ≠ 165°

∠A = 36°        ∠B = 15°       ∠C = 129°       is the only valid solution.

40)      ∠A = 16°        ∠B = ?       ∠C = ?

             a = 15           b = ?         c = 19

Use Law of Sines to find ∠C:

\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin 16}{15}=\dfrac{\sin C}{19}\rightarrow \quad \angle C=20^o\quad or \quad \angle C=160^o

If ∠C = 20°, then ∠B = 180° - (16° + 20°) = 144°

If ∠C = 160°, then ∠B = 180° - (16° + 160°) = 4°

Both result with ∠B as a positive number so both are valid solutions.

Solution 1:  ∠A = 16°        ∠B = 144°       ∠C = 20°    

Solution 2:  ∠A = 16°        ∠B = 4°       ∠C = 160°    

41)       ∠A = ?        ∠B = 75°       ∠C = ?

             a = 7           b = 30         c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{7}=\dfrac{\sin 75}{30}\rightarrow \quad \angle A=13^o\quad or \quad \angle A=167^o

If ∠A = 13°, then ∠C = 180° - (13° + 75°) = 92°

If ∠A = 167°, then ∠C = 180° - (167° + 75°) = -62°

Since ∠C cannot be negative then ∠A ≠ 167°

∠A = 13°        ∠B = 75°       ∠C = 92°       is the only valid solution.

42)      ∠A = ?         ∠B = 119°       ∠C = ?

             a = 34         b = 34           c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{34}=\dfrac{\sin 119}{34}\rightarrow \quad \angle A=61^o\quad or \quad \angle A=119^o

If ∠A = 61°, then ∠C = 180° - (61° + 119°) = 0°

If ∠A = 119°, then ∠C = 180° - (119° + 119°) = -58°

Since ∠C cannot be zero or negative then ∠A ≠ 61° and ∠A ≠ 119°

There are no valid solutions.

6 0
3 years ago
Please help b/c i don’t get this.
Montano1993 [528]

Answer:

A. false

B. false

C. true

D. true

E. false

Step-by-step explanation:

7 0
4 years ago
F(x) = 6 • (0.4)x. then determine which answer choice matches the graph you drew. (Please help)
ladessa [460]

Answer:B

Step-by-step explanation: It’s a decay function

6 0
4 years ago
Read 2 more answers
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