Question

The heights of six basketball players in inches are 75, 78, 77, 79, 83, and 85 What is the mean absolute deviation of the heights?

Answer 1

Answer:

Mean absolute deviation of the heights is 3.

Explanation:

Given the heights: 75, 78, 77, 79, 83, 85

Average value, X = $\frac{75+78+77+79+83+85}{6}$

                        = 79.5

Mean absolute deviation = $\frac{1}{n}$(/$x_{1}$ - X/ + /$x_{2}$ - X/ + /$x_{3}$ - X/ + /$x_{4}$ - X/ + /$x_{5}$ - X/ + /$x_{6}$ - X/)

Mean absolute deviation = $\frac{1}{6}$(/75 - 79.5/ + /78 - 79.5/ + /77 - 79.5/ + /79 - 79.5/ + /83 - 79.5/ + /85 - 79.5/)

                              =  $\frac{1}{6}$(4.5 + 1.5 + 2.5 + 0.5 + 3.5 + 5.5)

                              =  $\frac{1}{6}$(18)

                              = 3

The mean absolute deviation of the heights is 3.