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AnnyKZ [126]
2 years ago
11

The temperature at Jade's cabin was negative 13 ° Celsius when he got up in the morning. It dropped 2 ° Celsius by 10 a.m. and t

hen rose 8 ° Celsius by lunchtime.
What was the temperature at lunchtime?
Mathematics
1 answer:
Nitella [24]2 years ago
8 0

Answer:

19 ° Celsius

Step-by-step explanation:

13 -2 = 11 +8 = 19

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Complete the derivation of the formula for a cylinder
viva [34]

Answer:

2r(2r)

R

Pi/4

Pi times r cubed

Step-by-step explanation:

Believe it or leave it

4 0
3 years ago
What is the value of x when solving the equation Negative 2 x + (negative 8) = 2 x + 8 using algebra tiles?
ella [17]

Answer:

The Answer is A.) -4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve -9(t - 2) = 4(1-15).
snow_lady [41]

Answer:

t = 74 / 9

Step-by-step explanation:

-9(t - 2) = 4(1 - 15)

-9t + 18 = 4 - 60

-9t + 18 = -56

 -18      -18

-9t = -74

/-9     /-9

t = 74 / 9

t = 8.22

5 0
3 years ago
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Uniforms are sold in packages of 8 - the stores 127 employees will be given 3 uniforms
Mnenie [13.5K]
You need 48 packages for each employee to have 3 uniforms

3 0
3 years ago
How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
3 years ago
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