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NeTakaya
3 years ago
13

3n-4=14 what are the steps to this one

Mathematics
2 answers:
insens350 [35]3 years ago
5 0

Answer:

n=6

Step-by-step explanation:

3n-4=14

3n+4=14

the 4's cancel out, and u add 4 to the 14

14+4= 18

3n=18

then divide 3 by both sides

n=6

bekas [8.4K]3 years ago
3 0

Answer:

j

Step-by-step explanation:

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dmitriy555 [2]

Answer:

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Step-by-step explanation:

7x + 3(x - 2) - 4x + 8

7x + 3x - 6 - 4x + 8

Combine like terms:

6x + 2

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4 0
3 years ago
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Janine made a cylindrical vase in which the sum of the lateral area and area of one base
Vinil7 [7]
Is this multiple choice

5 0
3 years ago
X^3+9X^2–25X–33=0<br> Find The root of X??
Simora [160]

Answer:

x=-11, -1, and 3

Step-by-step explanation:

x^3+9x^2-25x-33=0

There are formulas to solve cubics, but that probably is not the way you are expected to go.  Here is a trial and error approach that works in this case.

Assume that the cubic can be factored and that the roots are r1, r2, and r3.  Then the factored form is

(x-r1)(x-r2)(x-r3)=0

This shows that the constant must equal the product of the roots.

(r1)(r2)(r3)=-33

One possibility is that the roots are integers.  In this case, a factor of 33 might work.  Prime factorization of 33 gives 3 and 11.  Try 3.  Then (x-3) is a factor.

Divide the cubic by (x-3).  It works. the result is

x^2+12x+11

This has factors of (x+11) and (x+1).  Therefore, the roots are 3, -1, and -11

6 0
3 years ago
How do you find the sale's price for a sneaker that is normally sold at $150 but is now being sold at a 23% discount?
Alex
You multiply $150 times 23%
or .23
this equals 34.5 which is the amount you will be taking off (the discount)
so then you subtract 150-34.5 which equals $115.50
6 0
3 years ago
Simplify: [5×(25)^n+1 - 25 × (5)^2n]/[5×(5)^2n+3 - (25)^n+1​]​
Alekssandra [29.7K]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
3 years ago
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