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Naddika [18.5K]
3 years ago
8

[(15 x 3) + 3] = (12-6) = N​

Mathematics
2 answers:
madam [21]3 years ago
8 0

Answer:

did you mean to put 2 equal signs in this?

Step-by-step explanation:

that would make this false because the first part equals 48 and the second equals 6 and since 48 doesn't equal 6 this is a false statement

adelina 88 [10]3 years ago
6 0

Answer:

45+3 = 6=N

48_6= N

42= N

:. N= 42

Step-by-step explanation:

:. N= 42

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-5/16=-0.3125

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Students held a canned food drive and collected 200 cans. The distribution of food collected is shown in the graph below. Based
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Dea writes the expression 0.25 + 0.76 + 0.75 + 0.24. She rewrites the expression using the commutative property. Which expressio
ipn [44]

Answer:

B )  0.25 + 0.75 + 0.76 + 0.24

Step-by-step explanation:

<u>commutative law of addition:-</u>

According to the commutative property of addition,changing the order of the numbers.we are adding doesn't change the sum.

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8 0
3 years ago
There is a mountain with 45 bat caves in a row. Every cave has at least 2 bats and there are 490 bats in all. Any 7 caves in a r
zhannawk [14.2K]

Answer:

12

Step-by-step explanation:

The first cave has 7 times more bats than the last cave.  So if the 45th cave has b bats, then the first cave has 7b bats.

There are 77 bats in every row of 7 caves.  So if there are 7b bats in the first cave, then there are 77−7b bats in caves 2 through 7.

Since there are also 77 bats in caves 2 through 8, that means cave #8 must have 7b bats.  Repeating this logic:

#1 = 7b

#2-#7 = 77−7b

#8 = 7b

#9-#14 = 77−7b

#15 = 7b

#16-21 = 77−7b

#22 = 7b

#23-28 = 77−7b

#29 = 7b

So the first 29 caves have 5(7b) + 4(77−7b) = 308 + 7b bats.

Now we do the same thing from the other end.  If cave #45 has b bats, then caves #39-#44 have 77−b bats.  And since caves #38-44 have 77 bats, then cave #38 has b bats.  Therefore:

#45 = b

#39-44 = 77−b

#38 = b

#32-37 = 77−b

#31 = b

So caves 31 through 45 have 3b + 2(77−b) = 154 + b bats.

Adding that to the first 29 caves, plus x number of bats in cave #30:

308 + 7b + x + 154 + b = 462 + 8b + x

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28 = 8b + x

x is a maximum when b is a minimum, which is b = 2.

28 = 8(2) + x

x = 12

There are at most 12 bats in the 30th cave.

8 0
3 years ago
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