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Valentin [98]
2 years ago
14

Solve the solution (25a²)½​

Mathematics
1 answer:
mina [271]2 years ago
5 0

Answer:

25/2 a^2 and the alternative form 12.5a^2

Step-by-step explanation:

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14. Find mMK please :)
MrRissso [65]

Answer:

Step-by-step explanation:

11) strategy:  since they tell us. indirectly,  that the length of  JK is the same as LM then we can set those two equal, solve for X  and then.. when we have X we can figure out the lenght of JK  and LM and then just divide that by 2 go get PK  ( :0 Player Killer ???  no , not that PK)    

solve JK and LM

3x + 23 =9x-19

42 = 6x

7 = x

now that we know x = 7 plug it into either equation to come up with the length of JK or LM .  I'll pick JK just b/c it was 1st

3(7) + 23 = JK

21+23 = JK

44 = JK

now take half of 1/2*JK= 22  that is PK    ( are you sure that 's not player killer?)

PK = 22

12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB

9x-20 = 5x + 28

4x = 48

X = 12

9(12) -20 = BG

88 = BG

2*88 + AB

176 = AB

13) done

14)  strategy: find the angle at L,  and that will also be the arc of MK

<em>copy and past the below</em> helpful trig functions into your computer

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

<em>copy and past the above</em> :

use which ever trig function you want , we have all the sides of the triangle, I'll use CAH

Cos(Ф) = 9/15

Ф = arcCos(9/15)

Ф = 53.13010°

arc MK = 53.13010°

15)   strategy:  arc JK is just 2 times MK

2*MK = 106.26020°

arc MK = 106.26020°

16) find arc JPK   strategy:  JPK is just the remaining part of a full circle of 360 - MK  = 253.7397°

arc JPK = 253.7397°

7 0
2 years ago
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