Find the value of a and b

Reposting becuase it want let me edit my last one and somebody spam answered it.

harkovskaia [24]

Answer:

5

5Step-by-step explanation:

If you use the distance formula you can solve it pretty easily. The distance formula is:

d = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2} \\$

The two points you want are A and D. A is (-1, -4) and D is (3, -1). Plug that into the formula...

d = $\sqrt{(3 - (-1))^2 + (-1 - (-4))^2}$

d = $\sqrt{4^2 + 3^2}$

d = $\sqrt{16 + 9}$

d = $\sqrt{25}$

5

I can solve it in a different way if you want me to.

8 0

3 years ago

you go to store with money [m]spend 3.40 after paing you have 9.50 left write a agelbraiic exprrision to find out how much [m] y

ankoles [38]

Answer:

X = 9.5 + m

Step-by-step explanation:

m = money spent

x = money you had at the beginning

x = 9.5 + m

Substitute m in for 3.4

X = 9.5 + 3.4

Solve for x

X = 12.9

You started with $12.90

6 0

3 years ago

Cody was 165\,\text{cm}165cm tall on the first day of school this year, which was 10\%10% taller than he was on the first day of

Doss [256]

Answer:

165 cm.

Step-by-step explanation:

Let h be the height of Cody on the first day of school last year.

We have been given that Cody was 165 cm tall on the first day of school this year, which was 10% taller than he was on the first day of school last year.

To find the height of Cody on the first day of school last year, we need to find h such that h plus 10% of h equals 165. We can represent this information in an equation as:

$h+10\%\text{ of }h=165$

$h+(\frac{10}{100}*h)=165$

$h+0.10*h=165$

$1.10*h=165$

Let us divide both sides of our equation by 1.10.

$\frac{1.10*h}{1.10}=\frac{165}{1.10}$

$h=150$

Therefore, Cody was 150 cm tall on the first day of school last year.

5 0

4 years ago

Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4

Vladimir79 [104]

Answer:

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ 2nd

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is $32y^{10}-24$

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ $32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ the same with the answer

∴ The expression $32y^{10}-24$ = 8( $y^{10}-3$ ) is completely factored

∵ The expression is $20y^{7}+10y^{2}$

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of $y^{7}$ and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ $20y^{7}+10y^{2}=10y^{2}(2y^{5}+1)$ ⇒ not the same with the answer

∵ The expression is $16y^{5}+12y^{3}$

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of $y^{5}$ and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ the same with the answer

∴ The expression $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ is completely factored

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ )

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$

3 0

3 years ago

The rectangular prism is to be sliced perpendicular to the shaded face is to pass through point A,perpendicular to the front fac

Alex_Xolod [135]

Answer:

<h2>C: 3 inches by 6 inches</h2>

Step-by-step explanation:

Notice that point A is a mid point. If we cut the prism though that point, perpendicular to the shaded face, it means the side of 4 inches will be divide in two equal parts, and the 3-6 inches face won't be cut.

Therefore, the dimensions of the cross section is 3 inches by 6 inches, which are the dimensions of the face that won't be cut, because they don't intersect with point A.

8 0

3 years ago

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Find the value of a and b​

Find the value of a and b