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frez [133]
3 years ago
6

HELP ASAP An office employee ears $600 weekly. Find the equivalent earnings if paid biweekly, semimonthly, monthly, and annually

Mathematics
1 answer:
beks73 [17]3 years ago
6 0

1200~bi-weekly

1200~semimonthly

2400~monthly

31,200~annually

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Felix wrote several equations and determined that only one of the equations has no solution. Which of these equations has no sol
Ilya [14]

Answer:

A. 3(x-2)+x=4x+6 has no solution.

Step-by-step explanation:

We are provided the subsequent data in the question:

We evaluate the presented expressions to find which equations have no answer.

1)  Image of solved equation is added below.

2)  Image of solved equation is added below

3)  Image of solved equation is added below

4)  Image of solved equation is added below

Equation 1 has no solution.

3 0
3 years ago
Read 2 more answers
Harry's dog weighs 10 3/8 pounds. What is the weight of Harry's dog written as a decimal?
Maru [420]

Answer:

10.375

Step-by-step explanation:

You can tell that 10 is going to be before the decimal because it's already a whole number, so all you have to do is figure out what 3/8 is as a decimal! In case you didn't know, to change a fraction to a decimal, you divide the numerator (the top number) by the denominator (the bottom number). In this case, you need to divide 3, the numerator, by 8, the denominator. 3/8 = 0.375.

So, put the 10 in front of the decimal point and you're done...the answer would be 10.375!

Have great day :3

3 0
3 years ago
What’s the answer <br> r+11+ Br= 29
kakasveta [241]

r= 18/1+b

B= -1 + 18/r

5 0
3 years ago
you buy 1.55 pounds of apples and 1.95 pounds of pears. Apples and pears sell for the same price per pound. The total​ cost, aft
Artemon [7]
Give me a second while I calculate my math
3 0
3 years ago
g find the 2 components of vector b = 2i + j - 3k, one parallel to a = 3i - j and another one perpendicular to a
nika2105 [10]

Answer:

The components of \vec{b} parallel and perpendicular to \vec {a} are \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j and \vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k, respectively.

Step-by-step explanation:

Let be \vec b = 2\,i+j-3\,k and \vec a = 3\,i-j, the component of \vec b parallel to \vec a is calculated by the following expression:

\vec b_{\parallel} = (\vec b \bullet \hat{a}) \cdot \hat{a}

Where \hat{a} is the unit vector of \vec a, dimensionless and \bullet is the operator of scalar product.

The unit vector of \vec a is:

\hat{a} = \frac{\vec {a}}{\|\vec a\|}

Where \|\vec {a}\| is the norm of \vec a, whose value is determined by Pythagorean Theorem.

The component of \vec{b} parallel to \vec {a} is:

\|\vec {a}\| = \sqrt{3^{2}+(-1)^{2}+0^{2}}

\|\vec {a}\| = \sqrt{10}

\hat{a} = \frac{1}{\sqrt{10}} \cdot (3\,i-j)

\hat{a} = \frac{3}{\sqrt{10}}\,i -\frac{1}{\sqrt{10}} \,j

\vec{b}\bullet \hat{a} = (2)\cdot \left(\frac{3}{\sqrt{10}} \right)+(1)\cdot \left(-\frac{1}{\sqrt{10}} \right)+(-3)\cdot \left(0\right)

\vec b \bullet \hat{a} = \frac{5}{\sqrt{10}}

\vec b_{\parallel} = \frac{5}{\sqrt{10}}\cdot \left(\frac{3}{\sqrt{10}}\,i-\frac{1}{\sqrt{10}}\,j  \right)

\vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j

Now, the component of \vec {b} perpendicular to \vec{a} is found by vector subtraction:

\vec{b}_{\perp} = \vec {b}-\vec {b}_{\parallel}

If \vec b = 2\,i+j-3\,k and \vec {b}_{\parallel} = \frac{3}{2}\,i-\frac{1}{2}\,j, then:

\vec{b}_{\perp} = (2\,i+j-3\,k)-\left(\frac{3}{2}\,i-\frac{1}{2}\,j  \right)

\vec b _{\perp} = \frac{1}{2}\,i+\frac{3}{2}\,j-3\,k

4 0
3 years ago
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