Question

A university class has 29 students: 14 are accounting majors, 9 are business majors, and 6 are history majors. The professor is planning to select two of the students for a demonstration. The first student will be selected at random, and then the second student will be selected at random from the remaining students. What is the probability that the first student selected is an accounting major and the second student is a history major

Answer 1

Answer:

0.1034 = 10.34% probability that the first student selected is an accounting major and the second student is a history major

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

14 account majors from a set of 29 students.

Then, 6 history majors from a set of 29 - 1 = 28 students.

So

$p = \frac{14}{29}*\frac{6}{28} = \frac{14*6}{29*28} = 0.1034$

0.1034 = 10.34% probability that the first student selected is an accounting major and the second student is a history major