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3 years ago

5

At a middle school, 74 students have freckles. There are 258 students in the school. To the nearest tenth of a percent, what per

cent of the students have freckles?
A 18.4%
B 28.7%
C 34.6%
D 40.2%

2 answers:

adell [148]3 years ago

7 0

Answer:

28.7

Step-by-step explanation:

0.2868 =

28.68 =

28.7%

Tpy6a [65]3 years ago

3 0

I feel like it’s be B. or C. but im not sure

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Let f be a function of two variables that has continuous partial derivatives and consider the points

Sergeu [11.5K]

Answer:

The directional derivative of f at A in the direction of $\vec{u}$ AD is 7.

Step-by-step explanation:

Step 1:

Directional of a function f in direction of the unit vector $\vec{u}=(a,b)$ is denoted by $D\vec{u}f(x,y)$ ,

$D\vec{u}f(x,y)=f_{x}\left ( x ,y\right ).a+f_{y}(x,y).b$ .

Now the given points are

$A(8,9),B(10,9),C(8,10) and D(11,13)$ ,

Step 2:

The vectors are given as

AB = (10-8, 9-9),the direction is

$\vec{u}_{AB} = \frac{AB}{\left \| AB \right \|}=(1,0)$

AC=(8-8,10-9), the direction is

$\vec{u}_{AC} = \frac{AC}{\left \| AC \right \|}=(0,1)$

AC=(11-8,13-9), the direction is

$\vec{u}_{AD} = \frac{AD}{\left \| AD \right \|}=\left (\frac{3}{5},\frac{4}{5} \right )$

Step 3:

The given directional derivative of f at A $\vec{u}_{AB}$ is 9,

$D\vec{u}_{AB}f=f_{x} \cdot 1 + f_{y}\cdot 0\\f_{x} =9$

The given directional derivative of f at A $\vec{u}_{AC}$ is 2,

$D\vec{u}_{AB}f=f_{x} \cdot 0 + f_{y}\cdot 1\\f_{y} =2$

The given directional derivative of f at A $\vec{u}_{AD}$ is

$D\vec{u}_{AD}f=f_{x} \cdot \frac{3}{5} + f_{y}\cdot \frac{4}{5}$

$D\vec{u}_{AD}f=9 \cdot \frac{3}{5} + 2\cdot \frac{4}{5}$

$D\vec{u}_{AD}f= \frac{27+8}{5} =7$

The directional derivative of f at A in the direction of $\vec{u}_{AD}$ is 7.

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3 years ago

Use the geometric mean to find the value of e

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Answer:

suppose,

a=6

b=24

then we know that,

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A recipe calls for using 3/4 cup of brown sugar for each 2/3 cup of white sugar. How many cups of brown sugar are used per cup o

expeople1 [14]

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Answer:

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