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Alenkinab [10]
3 years ago
7

F(x) = 10-x and g(x) = x2 + 1 What is g(8) + f(7)

Mathematics
1 answer:
Olin [163]3 years ago
6 0
Plug in 8 for g(8) to get 8(2) + 1 which is equal to 17, plug in 7 for f(x) to get 10-7 which is equal to 3. 17 + 3 is equal to 20 which means g(8) + f(7)= 20
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The SKELD ship has 186 crewmates divided as evenly as possible into 8 teams. How many crewmates are in each team? Show your work
galben [10]

Answer:

There is 23 crewmates in a group i got this by dividing 186x8 but this number is uneven so i rounded :)

7 0
3 years ago
When an object falls freely, the formula for the distance it falls is d= 4.9t^2 where d is
german

Answer:

a) 122.5 m ; b) 10 s

Step-by-step explanation:

Just use the given equation and plug in what you know.

a)

d = 4.9t^2

d = 4.9(5^2)

d = 4.9 * 25

d = 122.5 m

b)

d = 4.9t^2

490 = 4.9t^2

100 = t^2

t = 10 s

3 0
3 years ago
Read 2 more answers
Help?? This question is gonna be similar to a test question tommorow i do not understand
tigry1 [53]
You should calculate( the area of a circle of radius 15 cm ) minus the area of the circle of radius (15 cm - width of the frame). I am not able to read the number, sorry. 
That is the surface area of the frame.

Then, if area of circle radius is 100%, the % of face of the clock is:

(100xareaCircle(15cm-widthframe))/areaCircle15cm


8 0
3 years ago
Start at 3. Create a pattern that multiples each number by 3. Stop when you have 5 numbers
Pachacha [2.7K]
3 9 27 81 243

Its 3 squared, cubed, then to the power of 4 and 5
6 0
3 years ago
Read 2 more answers
Which of the following absolute value equations has no solutions?Group of answer choices
Amiraneli [1.4K]

The absolute value measures the distance a number is away from the origin (zero) on the number line. A number can be to the left or right of zero on the number line, but the distance away from zero is always positive. Graphically:

In other words:

• If d is positive and

\begin{gathered} |x|=d \\ \text{ then} \\ x=d\text{ or }x=-d \end{gathered}

• If d is negative and

\begin{gathered} |x|=-d \\ \text{then} \\ \text{ No solution, because distance (d) can not be negative.} \end{gathered}

Therefore, the equation that has no solutions is:

\boldsymbol{|x|=-3}

3 0
1 year ago
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