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bonufazy [111]
3 years ago
13

Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1? 5,–1, –7, –13, –19,

Mathematics
2 answers:
Mama L [17]3 years ago
6 0

Answer:

sorry not having idea about the answer

vodomira [7]3 years ago
6 0

Answer:

Hello,

f(n)=f(n-1)+6

Step-by-step explanation:

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Svetllana [295]

Answer:

1.5x=6

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Step-by-step explanation:

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Find three real numbers​ x, y, and z whose sum is 6 and the sum of whose squares is as small as possible. g
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We're minimizing x^2+y^2+z^2 subject to x+y+z=6. Using Lagrange multipliers, we have the Lagrangian

L(x,y,z,\lambda)=x^2+y^2+z^2+\lambda(x+y+z-6)

with partial derivatives

\begin{cases}L_x=2x+\lambda\\L_y=2y+\lambda\\L_z=2z+\lambda\\L_\lambda=x+y+z-6\end{cases}

Set each partial derivative equal to 0:

\begin{cases}2x+\lambda=0\\2y+\lambda=0\\2z+\lambda=0\\x+y+z=6\end{cases}

Subtracting the second equation from the first, we find

2x-2y=0\implies x=y

Similarly, we can determine that x=z and y=z by taking any two of the first three equations. So if x=y=z determines a critical point, then

x+y+z=3x=6\implies x=y=z=2

So the smallest value for the sum of squares is 2^2+2^2+2^2=12 when (x,y,z)=(2,2,2).
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Answer:

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