Ask question

Ask question

All categories

scoundrel [369]

3 years ago

14

Consider the statement: 4−3+5=−6+8+4. This is a mathematically correct sentence.Is the sentence true or false? Explain how you k

now.

2 answers:

Vladimir79 [104]3 years ago

7 0

Answer:

This is true because 6 does infact equal 6

Step-by-step explanation:

First see if the solution is true by seeing if x = x

So solve both sides

4-3+5 = -6+8+4

1+5 = 2+4

6 = 6

krek1111 [17]3 years ago

5 0

True this answer is true

You might be interested in

Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

3 0

3 years ago

Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (

Vladimir79 [104]

Answer:

Factors: $(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

Step-by-step explanation:

We are given a polynomial:

$f(x)=x^4-x^3-2x-4$

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

$f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

8 0

3 years ago

Use the functions f(x)=4x+10 and g(x)=2x-4. <br><br> Find the value of g(5)

a_sh-v [17]

Answer:

6

Step-by-step explanation:

g(5) represents x=5

you would substitue 5 for x in g(x)=2x-4

g(5)=2(5)-4

g=6

8 0

3 years ago

The toy shop stocks tricycles and go-carts.

Mandarinka [93]

Total number of wheels in the toy shop = 37 wheels

Number of wheels for tricycles = 3

Number of wheels for go-carts = 5

Since the total number of tricycles and go-carts are not given, we solve this question using Assumption.

Let's assume: We have 4 tricycles and 4 go-carts

(4 x 3) + (4 x 5)

= 12 + 20

= 32 wheels. This assumption is wrong.

Let's assume: We have 4 tricycles and 5 go-carts

(4 x 3) + (5 x 5)

= 12 + 25

= 37 wheels. This assumption is correct.

Therefore, we have 4 tricycles and 5 go-carts in the toy shop.

To learn more, visit the link below:

brainly.com/question/23264573

3 0

3 years ago

The length of a rectangle board is 10 centimeters longer than its width. The width of the board is 26 centimeters. The board is

Troyanec [42]

Answer:

Area of each piece = 104 $cm^{2}$

Possible dimensions are 26 cm by 4 cm, 13 cm by 8 cm.

Step-by-step explanation:

Given that:

Dimensions of the rectangular board as:

Length of the board is 10 cm longer than its width.

Width of the board = 26 cm

Length of the board = 26 + 10 = 36 cm

The rectangular board is divided into 9 equal pieces.

To find:

Area of each piece and

the possible dimensions of each piece = ?

Solution:

First of all, let us calculate the area of bigger rectangular board.

Area of a rectangle is given by the following formula:

$Area = Length \times Width$

Area = 26 $\times$ 36 $cm^2$

Area of each smaller rectangle = $\frac{26\times 36}{9} = 104\ cm^2$

To find the possible dimensions, we need to find the factors of 104.

104 = 26 $\times$ 4

104 = 13 $\times$ 8

Therefore, the Possible dimensions are 26 cm by 4 cm

and

13 cm by 8 cm.

5 0

3 years ago