Answer:
3125
Step-by-step explanation:
The model has three options, each one of which you can either take or not take.
Let us represent taking an option with 1 and not taking an option with 0
1. 0 0 0 ( taking none of the options)
2. 0 0 1
3. 0 1 0
4. 0 1 1
5. 1 0 0
6. 1 0 1
7. 1 1 0
8. 1 1 1 ( taking all three options)
Also you have a choice of four different colors, therefore, total number of possible combinations are
8*4= 32
Hence the largest number of cars having same options and colors is
100,000/32
3125 cars
Answer:
Step-by-step explanation:
Your possibility is pretty slim, but you still have a chance of choosing either of the two. So you would add them all up so 49 total. 49 7/8
29
-10
------
19
*3
--------
57 divided by 3 = 19
19
-10
------
9 + 2 = 11
11 - 7 = 4
Like this?
is acute, then slope is positive;