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Dima020 [189]
3 years ago
13

What is the solution to 9x−6<21?

Mathematics
1 answer:
Alisiya [41]3 years ago
7 0

Answer:

x > 3

Step-by-step explanation:

1) Add 6 to both sides.

9x > 21 + 6

2) Simplify 21 + 6 to 27.

9x > 27

3) Divide both sides by 9.

x >  \frac{27}{9}

4) Simplify 27/9 to 3.

x > 3

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>option</u><u> </u><u>B</u><u>.</u><u> </u><u>x</u><u> </u><u>></u><u> </u><u>3</u>.

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A right triangle has a hypotenuse of 10 feet and a leg of 6 feet. What is the length of the other leg?
Artemon [7]

Answer:

The other length of the leg is <em>8 feet.</em>

Step-by-step explanation:

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2 years ago
Find the value of the expression below for x=10<br><br> x ^2 - 2 (x + 5)
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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
A pentagonal prism has a height of 9 feet, and each base edge is 3 feet. Find the volume. Round your answer to the nearest hundr
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Height of the pentagon = 9 ft

Edge of base = 3 ft

area of pentagon = \frac{s^{2}n}{4 tan\left ( \frac{180}{n} \right )}

s is the length of any side = 3

n is the number of sides = 5

tan is the tangent function calculated in degrees

\\ \\\\area of pentagon = \frac{3^{2}(5)}{4 tan\left ( \frac{180}{5} \right )}\\\\\\area of pentagon = \frac{9(5)}{4 tan\left ( 36 \right )}\\\\area of pentagon = \frac{45}{4  ( 0.7265 )}\\\\area of pentagon = \frac{45}{2.906}\\\\area of pentagon = 15.4852

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Volume of the pentagon = 15.4852 (9)

Volume of the pentagon = 139.366

Volume of the pentagon = 139.37 cu.ft


5 0
3 years ago
Read 2 more answers
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