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Leokris [45]
3 years ago
13

A bank has a special vault for valuable items . It has 3 dials that operate the combination . The first dial has the numbers fro

m 1 to 100 , the second and third each have the 26 letters of the alphabet . In order to open the vault, the bank manager must correctly set each dial . How many possible combinations are there for this vault?
100

52

26

67,600

152
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
7 0

Answer:

There are 67,600 possible combinations for this vault.

Step-by-step explanation:

First dial: 100 possible values

Second dial: 26 possible values

Third dial: 26 possible values.

How many possible combinations are there for this vault?

Multiplication of these values. So

100*26*26 = 67600

There are 67,600 possible combinations for this vault.

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C = 2πr  or  C = πd

Diameter d = 57 cm

C = πd

C = π*57 = 57π

C ≈ 57 * 3.14159 = 179.07063

Exact circumference is  57π  cm  or

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3 years ago
Plz :<
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Answer:

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Step-by-step explanation:

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3 years ago
Anika is hiking on a rectengular trail at the nation park there are four resting spots along the corners of the trail on the map
Drupady [299]

Answer:

The perimeter is 14 units

<em></em>

Step-by-step explanation:

Given

A = (-2,2)

B = (1,2)

C = (1,-2)

D = (-2,-2)

Required

Determine the perimeter

To do this, we simply calculate the distance between the sides of the rectangle i.e. AB, BC, CD and DA.

Distance (d) is calculated using:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

For AB

A = (-2,2) --- (x_1,y_1)

B = (1,2) --- (x_2,y_2)

AB = \sqrt{(-2 - 1)^2 + (2 - 2)^2} = \sqrt{9} = 3

For BC

B = (1,2) --- (x_1,y_1)

C = (1,-2) --- (x_2,y_2)

BC = \sqrt{(1-1)^2 + (2--2)^2} = \sqrt{16} = 4

For CD

C = (1,-2) --- (x_1,y_1)

D = (-2,-2) --- (x_2,y_2)

CD = \sqrt{(1 - -2)^2 + (-2 -- 2)^2} = \sqrt{9} = 3

For DA

D = (-2,-2) --- (x_1,y_1)

A = (-2,2)  --- (x_2,y_2)

DA = \sqrt{(-2--2)^2 + (-2-2)^2} = \sqrt{16} = 4

So, the perimeter (P) is:

P = AB + BC + CD + DA

P = 3 +4 + 3 + 4

P = 14

<em>The perimeter is 14 units</em>

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Answer:

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