9514 1404 393
Answer:
- driver's tank: 30,427 lb
- farmer's tank: 12,811 lb
Step-by-step explanation:
The formula for the volume of a cylinder is ...
V = πr^2·h . . . radius r, height h
The radius of the driver's tank is half its diameter, so is (8 ft)/2 = 4 ft. Then the volume of that tank is ...
V = π(4 ft)^2·(19 ft) = 304π ft^3
Each cubic foot of gasoline has a mass of ...
(1728 in^3/ft^3)(0.0262 lb/in^3) = 45.2736 lb/ft^3
Then the total mass in the driver's full tank is ...
(304π ft^3)(45.2736 lb/ft^3) ≈ 43,238.3 lb
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The farmer's tank is a scaled-down version of the driver's tank. It's volume will be scaled by the cube of the linear scale factor, so will be (2/3)^3 = 8/27 of the volume of the driver's tank.
The farmer's tank will hold a mass of (43,238.3 lb)(8/27) ≈ 12,811 lb.
The amount remaining in the driver's tank is 43,238 -12,811 = 30,427 lb.
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