First, put it into slope/intercept form so you can see what you've got.
"Slope/intercept form" is <em> y = everything else</em> .
So that means you have to take the equation you have and "solve it for 'y' ".
<u>2y - 10x = 20</u>
Add 10x to each side: 2y = 10x + 20
Divide each side by 2 : <em> y = 5x + 10</em>
There it is.
Now that you have it in that form, you can just look at it and see that the
slope of the line on the graph is 5, and the line crosses the y-axis at 10.
And that's exactly the information you need to graph it. On your graph,
mark a little dot on the y-axis at 10, and draw a line through that dot
with a slope of 5.
Answer:
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Explanation:
We cannot have negative numbers under the square root, if we wanted the result to be some real number.
The stuff under the square root must be 0 or larger.
This means the x+2 must be 0 or larger.
Similarly, the 5-x must be 0 or larger. But wait, we cannot have 0 in the denominator (or else we have a division by zero error), so 5-x must be larger than 0.
5-x > 0
5-x+x > 0+x
5+0 > 0+x
5 > x
x < 5
Combine both and to find the domain is
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Visual confirmation is shown below. I used Desmos which is a free graphing app.
- f(x) = sqrt(x+2) is in red
- g(x) = sqrt(5-x) is in blue
- h(x) = f(x)/g(x) is in green
The green curve is what we're after. It's between x = -2 and x = 5
We include -2, but exclude 5.
Take note of the closed endpoint at x = -2, and also the vertical asymptote at x = 5. The curve approaches this asymptote but never actually touches it. Think of an electric fence you can get closer to, but not actually touch.
Answer:
b= 7
Step-by-step explanation:
24= 3b + 3
24-3 = 3b
21= 3b
21/3 = b
7 = b