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agasfer [191]
3 years ago
5

I need help with its slope practice

Mathematics
1 answer:
devlian [24]3 years ago
7 0

Answer:

m = -1

Step-by-step explanation:

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In right ∆ABC the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find BC if AD = 8 cm and DH = 4 cm.
alina1380 [7]
Check the picture below.

notice that the triangle ADH, since the segment AL is an angle bisector, meaning  it cuts the angle A in two equal halves, then the triangle ADH is only using half of A.

5 0
4 years ago
Read 2 more answers
State the value of the discriminant for the equation,<br> 3x^2 + 7x + 3 = 0
Irina-Kira [14]

Answer: 13

Step-by-step explanation:

If you remember the quadratic equation formula;

x=\frac{-b\frac{+}{}\sqrt{b^2-4ac}  }{2a}

You can easily extract what is under the root to find the discriminant.

b^2-4ac=?\\

a = 3

b = 7

c = 3

(7)^2-4(3)(3)\\49-36=13

7 0
3 years ago
Nicole sold 1 cherry pie and 9 pumpkin pies for $60. Lisa sold 11 cheery pies and 4 pumpkin pies for $90. what's the cost each o
zubka84 [21]
X= cost per cherry pie
y= cost per pumpkin pie

NICOLE
1x + 9y= $60

LISA
11x + 4y= $90


STEP 1
multiply Nicole's equation by -11

-11(1x + 9y)= -11($60)
multiply -11 by all terms

(-11 * x) + (-11 * 9y)= (-11 * 60)

-11x - 99y= -660


STEP 2
add Nicole's new equation from step 1 to Lisa's equation to solve for y (using the elimination method)

-11x - 99y= -660
11x + 4y= 90
the x terms "cancel out"

-95y= -570
divide both sides by -95

y= $6 per pumpkin pie


STEP 3
substitute y value into either original equation to solve for x

x + 9y= $60

x + 9(6)= 60

x + 54= 60
subtract 54 from both sides

x= $6 per cherry pie


CHECK
11x + 4y= $90
11(6) + 4(6)= 90
66 + 24= 90
90= 90


ANSWER: Each cherry pie costs $6 and each pumpkin pie costs $6.

Hope this helps! :)
3 0
3 years ago
What is 15x+8y less than or equal to 64
navik [9.2K]
Less than, because if you add 15+8 it equals 23 so less than
5 0
4 years ago
Locate the absolute extrema of the function on the closed interval:<br> y = 3x^(2/3) - 2x, [-1, 1]
Alecsey [184]
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
7 0
3 years ago
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