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Billy makes $5 a week in allowance plus $4 for each lawn that he mows.

Ad libitum [116K]

Answer:

$15 < $4n + $5

Step-by-step explanation:

We know that Billy needs to make more than $15 between his allowance and the lawns that he mows. This means our inequality should include $15<. Also, since Billy will make $4 per lawn, that means we need to multiply $4 by the number of lawns he needs to mow, n: $4n. So far we have the following: $15<$4n. Next, we know that he makes $5 each week, on top of what he makes mowing each law. This means we need to add the $5 to the $4n. When we put all of these pieces together, we will get the following inequality: $15<$4n+$5

7 0

3 years ago

Evaluate 3+(−4)−8−(−1)

castortr0y [4]

Answer: - 8

Step-by-step explanation:

3+(−4)−8−(−1)

3 - 4 - 8 + 1

3 - 12 + 1

-9 + 1

- 8

4 0

4 years ago

Read 2 more answers

Y greater than or equal to x + 4

tatiyna

See the attached files

<h2>Explanation:</h2>

Here we have the following inequality:

$y>x+4$

In order to graph the shaded region, we have to graph the equation of the line $y=x+4$ whose slope is $m=1$ and y-intercept $b=4$ . So the graph of the line is shown in the First Figure below.

To find the shaded region we need to have a look at the symbol > that indicates that the shaded region is above the graph of the line and. Since this doesn't include the symbol =, then the line is dotted. Therefore, the resulting region is shown in the second Figure.

<h2>Learn more:</h2>

Shaded regions: brainly.com/question/9611462

#LearnWithBrainly

5 0

3 years ago

The force of gravity, F, exerted between two objects is equal to the product of the gravitational constant, G, the mass of the f

NeTakaya

The force of gravity is when the distance between two objects is d is:

F=(G*m1*m2)/d^2

7 0

3 years ago

An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.

Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0. $\overline 1$ yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0. $\overline 1$ yd. = (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel pad, m₁ = ρ × V₁

∴ The mass of the steel pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0

3 years ago