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ycow [4]
3 years ago
11

Jenny finds from a survey that about 20% of the students at her school do homework on Friday nights. If there are 567 students a

t the school, which is the closest to the number of students who do homework on Friday nights?
110 students 110 students 130 students 130 students 150 students 150 students 170 students
Mathematics
1 answer:
stellarik [79]3 years ago
8 0

Answer:

The answer is 110 Students

Step-by-step explanation:

You can find this out by multiplying 567 by .20, after you do this you will achieve an answer of 113.4 which is closet to 110.

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The answer is 7x so I this helps you please thank me plz bye
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Function g is a transformation of the parent exponential function, f(x)=2^2 . Which graph shows function g? g(x)2^x+3
anyanavicka [17]

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4 0
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Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
grandymaker [24]

Solution:

There is no saddle point (DNE). However, there is local maximum at (1, 1/2) for the given function.

Explanation:

we have function of two variables f(x,y)= 9-2x+4y-x^2-4y^2

we will find the values by partial derivative with respect to x,y,xy

f_{x}= -2 -2x

f_{y}= 4 -8y

to find the saddle point we should first find the critical points so equate

-2 -2x=0 and   4 -8y=0

we get x= 1  and y =1/2 so, critical points are (1,1/2)

to find local maximum or minimum we have to find f_{xx},  f_{yy} and f_{xy}

formula is f_{xx} *f_{yy} - f^{2_{xy} } =0

f_{xx} = -2

f_{yy} = -8

f^{2_{xy} } =0

putting values in formula

(-2)*(-8) -0 =16 > 0, and f_{xx}< 0  and f_{yy}<0

so, here we have local maximum

we have no saddle point for this function by using the same formula we used to find extrema.



4 0
3 years ago
Read 2 more answers
A scientist kept 100 grams of a radioactive material in a container. After 280 days, he observed that 25 grams of the radioactiv
Wittaler [7]

Answer:

B: About 50 grams of the material was left in the container after 140 days.

Step-by-step explanation:

Radioactive materials decay at a rate called "half-lives." After a certain amount of time, the grams of radioactive material will be reduced to half. After that same amount of time again, the material will be reduced to half of the half.

1/4 is equal to 1/2 times 1/2. So, when 1/4 of the material remains, two half-lives have elapsed.

The question states that after 280 days, 25 grams of the material was left in the container. 25 grams is 1/4 of the original 100 grams that the scientist started with at time = 0 days.

When 25 grams of material remain, two half-lives have elapsed. 280 days equals two half-lives for this material. So 140 days (half of 280 days) equals one half-life for this material.

After 280 days (two half-lives), one fourth of the material (25 grams) will remain.

After 140 days (one half-life), half of the material (50 grams) will remain.

5 0
3 years ago
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