Let X is the random number Erik thinks of, and Y is the random number Nita thinks of.
Both X and Y are in the range from 0 to 20.
<span>X<=20
Y<=20
If the difference between their two numbers is less than 10, then Erik wins.
The difference between the two numbers can be written X-Y, or Y-X depending on which number (X or Y) is greater. But we do not know that. In order not to get negative value, we calculate absolute value of X-Y, written |X-Y| which will give positive value whether X is greater than Y or not.
If |X-Y|<10 Erik wins.
</span><span>If the difference between their two numbers is greater than 10, then Nita wins.
</span><span>If |X-Y|>10 Nita Wins
</span>
Answer:
Answer Choice A (8, eight)
Step-by-step explanation:
To begin, add all of the marbles together. When finished, the answer should be 20. Because the variable 20 equals 100, you divide 4 by 100. You will get 0.04 as a result. This multiplied by 20 equals 8. Finally, the answer is A.
In the first reaction, Gold (Au) gets 3 electrons and became Gold. In the second reaction, Iodine (I) loses 2 electrons and became Iodine.
<h3>What are cations and anions?</h3>
When the atom loses the election then it is called a cation and when it gains the electron is called an anion.
Two reactions are given.
First reaction;
Au³⁺ + 3e⁻ ⇒ Au
In the first reaction, Gold (Au) gets 3 electrons and became Gold.
Second reaction;
2I⁻ ⇒ I₂ + 2e⁻
In the second reaction, Iodine (I) loses 2 electrons and became Iodine.
More about the cation and the anion link is given below.
brainly.com/question/1659592
Answer:
Total wrapping papers Serena and her grandmother = 51/10
Step-by-step explanation:
Serena's wrapping paper for parents:
sq meters
Grandmother's wrapping paper:
sq meters
In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.
i.e.
Total papers = Serena's wrapping paper + Grandmother's wrapping paper
Therefore, total wrapping papers Serena and her grandmother = 51/10
Answer:
C
Step-by-step explanation:
