<span>(3x - 1)( x + 5)(4x - 3) = 12x^3 + 47x^2 - 62x +15 </span>
<span>(3x^2 –
x + 15x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>(3x^2 +
14x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>12x^3 –
9x^2 + 56x^2 – 42x – 20x + 15 = <span>12x^3 +
47x^2 - 62x +15 </span></span>
<span>12x^3 –
47x^2 - 62x + 15 = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span> </span>
Using algebra
n and n+2 are the integers
n*(n+2)=288
n^2+2n=288
n^2+2n-288=0
288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2
factor(n+18)(n-16)=0
n+18=0
n=-18
n+2=-16
this is one solution
n-16=0
n=16
n+2=18
this is another solution
as you can see, it's just a matter of factoring 288using arithmetic...√288=16.97≈1716 and 18 are the integers (as well as -16 and -18)
If the line is parallel to y=-x+4, the line must have the same slope.
So, the slope of your line is -1.
Now we need to find the y intercept. We should use the point given.
y=mx+b
0=-1(5)+b
b=5
Equation: y=-x+5
I believe since ABD is 60, DBC is also 60 and then ABC is 120
