All categories

2 years ago

The sum of y and the difference of 9 and j as an expression

Mathematics

1 answer:

-BARSIC- [3]2 years ago

4 0

Answer: I think it would be Y+(9-j)

You might be interested in

QUESTION 1 - 1 POINT

guajiro [1.7K]

Answer + Step-by-step explanation:

the inequality by finding the boundary line, then shading the appropriate area.

y > − 5/2x − 5

(anything in shaded region)

8 0

2 years ago

The area of circle B is 121 times greater than the area of circle A. The radius of circle B is 44. What is the radius of circle

xxMikexx [17]

Formula:
$\bigg( \dfrac{radius_1}{radius_2} \bigg)^2 = \dfrac{area_1}{area_2}$

Plug in the values:
$\bigg( \dfrac{r}{44} \bigg)^2 = \dfrac{1}{121}$

Simplify LHS:
$\dfrac{r^2}{1936} = \dfrac{1}{121}$

Multiply by 1936 on both sides:
$r^2 = \dfrac{1936}{121}
$

Simplify RHS:
$r^2 = 16$

Square root both sides:
$r = 4$

Answer: The radius is 4 units. (Answer B)

5 0

3 years ago

Find the missing number so that the equation has no solutions. 5x+1-3x=_x+13

joja [24]

Answer:

You may just add 2 in the spot. Moreover, you get no solution.

Step-by-step explanation:

Hope this helped!

7 0

3 years ago

Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

$\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$

$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

6 0

3 years ago

Read 2 more answers

Lucy's dog weighs nine and seventy five hundredths kilograms . Write in expanded form.

MissTica

9 + 0.07 + 0.005 this is expanded form i hope this is what u wanted as an answer

7 0

3 years ago

The sum of y and the difference of 9 and j as an expression​

The sum of y and the difference of 9 and j as an expression