What is the output of the loop for count in range(5): print(count)?

(1) Prompt the user to enter a string of their choosing. Output the string.

barxatty [35]

Answer:

See solution below

See comments for explanations

Explanation:

import java.util.*;

class Main {

public static void main(String[] args) {

//PrompT the User to enter a String

System.out.println("Enter a sentence or phrase: ");

//Receiving the string entered with the Scanner Object

Scanner input = new Scanner (System.in);

String string_input = input.nextLine();

//Print out string entered by user

System.out.println("You entered: "+string_input);

//Call the first method (GetNumOfCharacters)

System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));

//Call the second method (OutputWithoutWhitespace)

System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));

}

//Create the method GetNumOfCharacters

public static int GetNumOfCharacters (String word) {

//Variable to hold number of characters

int noOfCharactersCount = 0;

//Use a for loop to iterate the entire string

for(int i = 0; i< word.length(); i++){

//Increase th number of characters each time

noOfCharactersCount++;

}

return noOfCharactersCount;

}

//Creating the OutputWithoutWhitespace() method

//This method will remove all tabs and spaces from the original string

public static String OutputWithoutWhitespace(String word){

//Use the replaceAll all method of strings to replace all whitespaces

String stringWithoutWhiteSpace = word.replaceAll(" ","");

return stringWithoutWhiteSpace;

}

6 0

3 years ago

You can use a(n) to call a function in response to an event?

uranmaximum [27]

Answer:

Simply put: A callback is a function that is to be executed after another function has finished executing — hence the name 'call back'. ... Functions that do this are called higher-order functions. Any function that is passed as an argument is called a callback function.

Explanation:

6 0

3 years ago

While you are working on your computer, it shuts down unexpectedly, and you detect a burning smell. When you remove the case cov

Virty [35]

Answer:

Replace the power supply

Explanation:

Usually, Capacitors burn up because of different factors.

- Exceeding operation voltage

- High Inverse voltage if is an electrolytic capacitor.

A tentative answer could be the battery, but usually the batteries damages are because wear out of them, that is, cycles of charging and discharging, a problem that could arise in the battery is related with the charge protection, this circuit cares that the battery only get the charge that it needs, in Li-po batteries is 3.7V, in some laptops is 24 V, if so the battery could explode or leaking acid.

The mother-board is the "brain" and the Random Access Memory (RAM), they consume a lot of energy and usually heat up, but doesn’t produce increasing of voltage and its feed it by voltage regulators.

The only valid option is the power supply because the energy comes from a rectifier (made with diodes) and a voltage regulator that step-down the DC voltage output if by any chance the voltage increase or a diode burns up in the power supply the coupling capacitors or input capacitors in the computer will fail.