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Stolb23 [73]
3 years ago
5

True or False: x is the same/equal to 1x

Mathematics
1 answer:
Katarina [22]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

Because you're multiplying by 1 so it stays the same value

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= x 3048

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faltersainse [42]

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-3

Step-by-step explanation:

A = midpoint

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Read 2 more answers
Multiply using FOIL or Table method (x + 4) (x + 5)
mylen [45]

Answer:

{x}^{2}  + 9x + 20

Step-by-step explanation:

1) Use FOIL method: (a + b) (c + d) = ac + ad + bc + bd.

{x}^{2}  + 5x + 4x + 20

2) Collect like terms.

{x}^{2}  + (5x + 4x) + 20

3) Simplify.

{x}^{2}  + 9x + 20

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>9x</u><u> </u><u>+</u><u> </u><u>20</u>.

5 0
3 years ago
In an experiment, some diseased mice were randomly divided into two groups. One group was given an experimental drug, and one wa
damaskus [11]

Answer:

D)Yes, because the difference in the means in the actual experiment was more than two standard deviations from 0.

Step-by-step explanation:

We will test the hypothesis on the difference between means.

We have a sample 1 with mean M1=18.2 (drug group) and a sample 2 with mean M2=15.9 (no-drug group).

Then, the difference between means is:

M_d=M_1-M_2=18.2-15.9=2.3

If the standard deviation of the differences of the sample means of the two groups was 1.1 days, the t-statistic can be calculated as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{2.3-(0)}{1.1}=2.09

The critical value for a two tailed test with confidence of 95% (level of significance of 0.05) is t=z=1.96, assuming a large sample.

This is approximately 2 standards deviation (z=2).

The test statistict=2.09 is bigger than the critical value and lies in the rejection region, so the effect is significant. The null hypothesis would be rejected: the difference between means is significant.

4 0
3 years ago
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