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sp2606 [1]
3 years ago
14

Pls help with this asap

Mathematics
1 answer:
Brut [27]3 years ago
4 0
The answer is A and D
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I believe the answer to question 2 is the first option, and the answer to question 3 is the last option

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-18 + (-6)<br> nton vann answer below:<br> idk what this is
EastWind [94]

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-24

Step-by-step explanation:

you add them like you would in addition but since they are both negative you keep the sign, making it -24

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Gnesinka [82]

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a is 25 b is 15 percent

Step-by-step explanation:

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Which is the range of the function f(x) =One-seventh(9)x?
shutvik [7]

Answer:

Option c: all real numbers greater than 0

Step-by-step explanation:

we have

f(x)=\frac{1}{7}(9^{x})

This is a exponential function of the form

f(x)=a(b^{x})

where

a is the initial value (y-intercept)

b is the base

r is the rate

b=(1+r)

In this problem we have

a=1/7

b=9

r=b-1 ----> r=9-1=8 -----> r=800%

using a graphing tool

see the attached figure

The domain is the interval ------> (-∞,∞)

The domain is all real numbers

The range is the interval ---------> (0,∞)

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6 0
4 years ago
Read 2 more answers
In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour
Lesechka [4]

Answer:

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=54 represent the sample mean  

\mu population mean (variable of interest)

\sigma=21 represent the sample standard deviation

n=16 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=1-0.9=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

4 0
4 years ago
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