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3 years ago

Please help me with this

Mathematics

1 answer:

rosijanka [135]3 years ago

4 0

Answer:

If the equation represent the situation the variable x represents the total amount of money Han made from mowing lawns.

Step-by-step explanation:

x=23

96-27=69

69/3=23

Jada made a total amount of 69 dollars from babysitting so Han made $23.

Have a nice day!

and can I maybe have brainliest? Thanks!

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Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0

4 years ago

Find the standard deviation of 21, 31, 26, 24, 28, 26

Vesnalui [34]

Given the dataset

$x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}$

We start by computing the average:

$\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26$

We compute the difference bewteen each element and the average:

$x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}$

We square those differences:

$(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}$

And take the average of those squared differences: we sum them

$\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69$

And we divide by the number of elements:

$\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5$

Finally, we take the square root of this quantity and we have the standard deviation:

$\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39$

8 0

3 years ago

The diagram shows a plan for fencing off a section of a public park to make a dog park. A wall that separates the park from a hi

Orlov [11]

Where’s the diagram?

3 0

3 years ago

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The lateral area of a cone is 558 ou cm ^2 . The radius is 31 cm. Find the slant height to the nearest

Kamila [148]

Answer:

83.8 cm

Step-by-step explanation:

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3 years ago

What are the zeros of this function?<br> Please let me know asap!!!

blagie [28]

Answer:

My best Gues is x=0 and x=6

Step-by-step explanation:

Because The zeroes of a function is where the line is equal to fx=0 which means it is where the line intercepts with the x axis. And the the line is on the x- axis touching 0 and it isn’t touching any negative number so it would have to be positive and would be 6.

6 0

2 years ago

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