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Harlamova29_29 [7]
3 years ago
6

Please help asap final exam

Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

i think it's b

Step-by-step explanation:

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Nothing can be done with this question!
8 0
4 years ago
In the lottery every week, 2,000,000 tickets are sold for $1 apiece. Say 4000 of these tickets pay off $30 each, 500 pay off $80
jarptica [38.1K]
The expected value is just the weighted average of how much one ticket wins. To calculate it, we need to find the probabilities of winning each dollar amount, multiply each probability with it's respective dollar amount, then find the sum.

Let's call the winnings from one ticket X:

P(X=30) = 4000/2000000 = 0.002

P(X=800) = 500/2000000 = 0.00025

P(X=1200000) = 1/2000000 = 0.0000005

E(X) = 30*P(X=30) + 800*P(X=800) + 1200000*P(X=1200000) = 0.06 + 0.2 + 0.6 = 0.86

The answer is $0.86
4 0
4 years ago
Pls help I need the answer quick
VashaNatasha [74]
Answer:
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4 0
3 years ago
Write the equation for the parabola that has x− intercepts (−2,0) and (1.2,0) and y− intercept (0,−4).
schepotkina [342]

Answer: The answer is 15y+4=25(x-1.6)^2.


Step-by-step explanation:  We are to find the equation of the parabola with x-intercepts (-2,0), (1.2,0) and y-intercept (0,-4).

Therefore, axis of symmetry is

x=\dfrac{1.2+2}{2}\\\\\Rightarrow x=1.6.

Let the equation of the parabola be y=a(x-1.6)^2+k.

Substituting the points (x,y)=(0,-4) and (1.2,0) in the above equation, we find that

-4=a(0-1.6)^2+k\\\\\Rightarrow k=-2.56a-4

and

0=a(1.2-1.6)^2+k\\\\\Rightarrow k=-0.16a.

Solving the above two equations, we get

a=-\dfrac{5}{3}~~\textup{and}~~k=-\dfrac{4}{15}.

So, putting the values of 'a' and 'k' in the equation of the parabola, we get

y=-\dfrac{5}{3}(x-1.6)^2-\dfrac{4}{15}\\\\\Rightarrow 15y+4=-25(x-1.6)^2.

Thus, the equation of the parabola is  15y+4=25(x-1.6)^2.


3 0
4 years ago
The circle with center 0 has a radius of 18 centimeters. If the length of arc AB=6 pie cm, what is the measure of x
Ilya [14]

Answer:

The x variable will equal 42

3 0
4 years ago
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