Y= (x-2)² + 5. We can write it as : y-5 = (x-2)². The general equation of a quadratic function is :
(y-k) = a(x-h)², where h and k are the vertex of the parabola and a, the coefficient which determines whether the parabola opens upward or downward.
So, y-5 = (x-2)²
Having said that we can say that the VERTEX( 2,5) and since a=1 (a>0) the parabola is open upward OR it passes by a MINIMUM (Then the vertex is minimum)
The domain (x- value) is all Real { x|x = -∞ to x=+∞}
The Range (y-value) is all y ≥ 5
I believe the midpoint is ( 2 1/2 , 3 1/2 )
Answer: you need to show what are the options
Step-by-step explanation:
Answer:
in terms of pi: A = 14,400pi
A = 14,400(3.14) is 45,216
Step-by-step explanation:
Area of a circle is pir^2
Radius = diameter / 2
Radius = 240 / 2 which is 120
A = pi(120)^2
A = 14,400pi
