The 12th decades every other day every three days and four days all have 12 in common I think
Answer:
The proportion of electric toothbrush prices are between 104.60 dollars and 108.20 dollars is 0.0099
Step-by-step explanation:
A set of electric toothbrush prices are normally distributed with a mean of 87 dollars and a standard deviation of 8 dollars.

Standard deviation = 
We are supposed to find proportion of electric toothbrush prices are between 104.60 dollars and 108.20 dollars i.e.P(104.60<x<108.20)

At x = 104.60

Z= 2.2
At x=108.20

Z= 2.65
Refer the z table for p value :
P(x<108.20)-P(x<104.60)=P(Z<2.65)-P(Z<2.2)=0.9960-0.9861=0.0099
Hence The proportion of electric toothbrush prices are between 104.60 dollars and 108.20 dollars is 0.0099
Hi pupil here's your answer ::
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The unit rate depicted in the graph is must be
3 laps in 4 minutes . As we can see in the graph that the point meets at the 3 laps and 4 minutes so this option must be suitable for the above question.
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hope that it helps. . . . . .
Answer:

Step-by-step explanation:
To solve this operation we need to find the common multiple of both denominators and solve for a.

Thus, the solution is 7(a -1) / (a+2)(a-5)