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3 years ago

Find the measure of the indicated angle that makes lines uand v parallel.

Mathematics

1 answer:

Rzqust [24]3 years ago

7 0

1. 135 ( corresponding angles)
2. 66 ( corresponding angles)
3. 118( alternative interior angles)

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The length of a rectangle is four times the width minus three. If the perimeter of the rectangle is 64 meters, what is the lengt

Nastasia [14]

Answer:

L = 25 m

Step-by-step explanation:

L = 4W - 3

perimeter = 2(L + W)

64 = 2(4W - 3 + W)

divide both sides by 2:

32 = 5W - 3

add 3 to each side:

5W = 35

divide both sides by 5:

W =7

L = 4(7) - 3 = 25

6 0

3 years ago

Lorena bought groceries for $102.34 and new shoes for $53.36. How much did Lorena spend on groceries and shoes altogether?

leonid [27]

Hello! So for this question, all you have to do is add the numbers up to get the total cost. Groceries were $102.34 and the new shoes were $53.36. 102.34 + 53.36 = 155.7. Lorena spent $155.70 total.

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3 years ago

Hihi please solve ( will mark brainliest ❥ )

Maksim231197 [3]

Answer:

use calculator and then solve it╮(─▽─)╭

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2 years ago

Two airliners are 1600 miles apart and heading toward each other at different altitudes. The first plane is traveling north at 6

viktelen [127]

In approximately around 2 hours and 10 mins

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3 years ago

A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As

Semenov [28]

Answer:

$0.2564\text{ pounds}$

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the $X$ percentile for the television weights, use the formula:

$X=\mu +k\sigma$ , where $\mu$ is the average of the set, $k$ is some constant relevant to the percentile you're finding, and $\sigma$ is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute $\mu=5$ , $k=1.282$ , and $\sigma=0.1$ :

$X=5+(1.282)(0.1)=5.1282$

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

$X=5+(-1.282)(0.1)=4.8718$

The difference between these two weights is $5.1282-4.8718=\boxed{0.2564\text{ pounds}}$ .

8 0

3 years ago

Read 2 more answers