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Evgesh-ka [11]
3 years ago
5

Find the measure of the indicated angle that makes lines uand v parallel.

Mathematics
1 answer:
Rzqust [24]3 years ago
7 0
1. 135 ( corresponding angles)
2. 66 ( corresponding angles)
3. 118( alternative interior angles)

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A triangle PQR is right angled at R, with PQ=80cm and R=60cm. find QR?<br> pythagorus theorem
algol13

Answer:

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

<u>by</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>

<u>h²</u><u>=</u><u>p²</u><u>+</u><u>b²</u>

80²=QR²+60²

QR²=80²-60²

QR=\sqrt{2800}

QR=20\sqrt{7}=52.9=53cm

<u>QR</u><u>=</u><u>5</u><u>3</u><u>c</u><u>m</u><u>.</u>

5 0
3 years ago
Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the
insens350 [35]

Answer:

So, the volume V is

V=\frac{14\pi}{3}

Step-by-step explanation:

We have that:

y=7x\\\\y=0\\\\x=1\\\\x=-4\\

We have the formula:

V=2\pi\int_a^b x(g(x)-f(x))\, dx\\\\g(x)>f(x).

We calculate the volume V, we get

V=2\pi\int_a^b x(g(x)-f(x))\, dx\\\\V=2\pi\int_0^1 x(7x-0)\, dx\\\\V=2\pi\int_0^1 7x^2\, dx\\\\V=2\pi\cdot 7\left[\frac{x^3}{3}\right]_0^1\\\\V=14\pi\left(\frac{1}{3}-\frac{0}{3}\right)\\\\V=\frac{14\pi}{3}

So, the volume V is

V=\frac{14\pi}{3}

We use software to draw the graph.

6 0
3 years ago
Find the y-intercept of the following equation. Simplify your answer.
jarptica [38.1K]
The y intercept is going to be 10x
4 0
3 years ago
Read 2 more answers
HELP! ASAP! Am I correct!?!?
LenKa [72]
It isn't because, it isn't consistent, and it doesn't follow any of the other answer choices. :)

3 0
3 years ago
Of all college degrees awarded in the United States, 50% are bachelor's degrees, 59% are earned by women, and 29% are bachelor's
Natasha2012 [34]

Answer:

  P(W|B) = 0.58

Step-by-step explanation:

The conditional probability formula tells you ...

  P(W | B) = P(W&B) / P(B)

  = 0.29/.050

  = 0.58

7 0
3 years ago
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