Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
All you have to do is multiply 0.3 by 8.
8×0.3=2.4
The dog will eat 2.4 kilograms of food in 8 days. Hope that helps!
Answer:
20+7x
Step-by-step explanation:
you'd multiply 2 by 5 and 2 by 3x which will give you 10+ 6x; Then add the others : 2(5+3x)+(x+10) would be 10+6x+x+10 so its 20+7x. .
Answer:
68⁰
Step-by-step explanation:
90 + 22 = 112
180 - 112 = 68
Answer:
14
pounds
Step-by-step explanation:
Here we have to use multiplication.
Yamin purchased 6 heads of cabbage.
The weight of each cabbage = 2 
First let's convert the mixed fraction 2 to improper fraction
2 = 
The weight of 6 heads of cabbage = 6 x
= 114/8
= 14 
We can reduce 2/8 = 1/4
= 14
Thank you.
