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3 years ago

The distance Grayson hikes VARIES DIRECTLY with how long it takes him. Write the EQUATION that matches this situation.

Mathematics

2 answers:

pickupchik [31]3 years ago

6 0

This makes no sense can u say it again

MArishka [77]3 years ago

3 0

Answer:

d=ct

Step-by-step explanation:

Let d be the distance Grayson hiked. Let t be the time he took for this hiking.

Given, d is directly proportional to t,

=> d = ct, where c is the constant of proportion.

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Answer:

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Given that

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3 years ago

Which of the following is equal to the rational expression when x=-1 or -7? (x+1)(x-1)/(x+7)(x+1) a. x+7/x-1 b. x-1/x+7 c. x+1/x

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4 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

The distance Grayson hikes VARIES DIRECTLY with how long it takes him. Write the EQUATION that matches this situation.​

The distance Grayson hikes VARIES DIRECTLY with how long it takes him. Write the EQUATION that matches this situation.