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Alla [95]
3 years ago
15

Hi there! Sorry to bother you, but can someone help me out with this?

Mathematics
1 answer:
Natalija [7]3 years ago
8 0

Answer:

#1

<u>Correct choice is </u>

  • B. m∠SAL = m∠TAL

#2

<u>Correct choice is</u>

  • A. SL = LT

#3

<u>Correct choice is</u>

  • A. TP bisect OM

#4

<u>Correct choice is</u>

  • B. ∠WYX and ∠WYZ are linear pairs

#5

<u>Correct choice is</u>

  • C. Perpendicular lines.
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7-c&lt;1 ?? HELPPPP!!!MEEEeee
sesenic [268]

Answer:

c>6, since a negative coefficient reverses the sign

Step-by-step explanation:

7-c<1

-c<-6

c>6

5 0
3 years ago
The left and right page numbers of an open book are two consecutive integers whose sum is 321
PIT_PIT [208]

Answer:

160,160

Step-by-step explanation:

let the first page be X

second one be x+1

x+x+1=321

2x=320

x= 320÷2=160

pages 160 161

6 0
3 years ago
Can you simpilfy the expression of: 6x-8y-5x+3y<br><br>Answer in comments
Romashka-Z-Leto [24]

Answer:

Hey there. Ur answer is x-5y

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Pls help me if you can
ExtremeBDS [4]

Answer:

Where is the question?

4 0
2 years ago
The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150
tiny-mole [99]

Answer:

The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150 indicated that the primary reason for setting up the plan was tax related.

This means that n = 200, \pi = \frac{150}{200} = 0.75

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.}{2} = 0.975, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.6996

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.8004

As percent:

0.6996*100% = 69.96%

0.8004*100% = 80.04%.

The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

6 0
3 years ago
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