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Solution:
To test the hypothesis is that the mean ozone level is different from 4.40 parts per million at 1% of significance level.
The null hypothesis and the alternative hypothesis is :
The z-test statistics is :
z = -1.37
The z critical value for the two tailed test at 99% confidence level is from the standard normal table, he z critical value for a two tailed at 99% confidence is 2.57
So the z critical value for a two tailed test at 99% confidence is ± 2.57
Conclusion :
The z values corresponding to the sample statistics falls in the critical region, so the null hypothesis is to be rejected at 1% level of significance. There is a sufficient evidence to indicate that the mean ozone level is different from 4.4 parts per million. The result is statistically significant.
Answer:
The answers for your two questions are the following
a)11.606 m
b) As the number of swings approaches infinity
Step-by-step explanation:
We are dealing with an exponential equation series, where the length of each swing can be represented as
l = [ 15 *(0.95)^(n-1) ]
n is the corresponding number of the swing.
So, for the first swing, n = 1
[ 15 *(0.95)^(1-1) ] = 15 m
a) How far with the pendulum travel on its 6th swing?
We just need to evaluate the previous formula for n = 6
[ 15 *(0.95)^(6-1) ] =
[ 15 *(0.95)^(5) ] =
[ 15 *(0.7737) ] =
[ 15 *(0.7737) ] = 11.606 m
b) How far will the pendulum swing before it essentially stops? Hint: This is an infinite geometric series.
We previously stated that the length of the arc of each swing can be represented as
l(n) = [ 15 *(0.95)^(n-1) ] , for n>=1
Since the function approaches zero if and only if n approaches infinity, we can say that the pendulum never stops.
Of course, this only happens mathematically, we can always fin a threshold for which the movement cannot be registered anymore.
Please see attached graph for a representation of the function
