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3 years ago

Someone please help me ! Its past due and Ive been busy.. D:

Mathematics

1 answer:

oee [108]3 years ago

4 0

Answer:

It's okay the first answer is right, $0.15

The store makes $4.20 off the rope

Step-by-step explanation:

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Easy question What is the answer??

ioda

Answer:

72.5

Step-by-step explanation:

6 0

3 years ago

Consider parallelogram △MNOP shown above.

Nina [5.8K]

To find the length of the sides of this parallelogram, we just have to calculate the length of each side and then proceed to find the perimeter.

The perimeter of the parallelogram is 13 units.

<h3>Perimeter of a Parallelogram</h3>

To calculate the perimeter of a parallelogram, we need the values of the length of the sides. However, if we have the details of two opposite sides, we can find the perimeter of the parallelogram because opposite sides are equal.

Length of MN = 2units

Length of MP = 4.5 units

The perimeter of MNOP can be calculated as

$perimeter = 2(MP + MN)$

We can substitute the values into the equation and solve

$perimeter = 2(MP + MN)\\perimeter = 2 * (4.5 + 2)\\perimeter = 2 * 6.5\\perimeter = 13$

The perimeter of the parallelogram is 13 units.

learn more on perimeter of a parallelogram here;

brainly.com/question/10919634

#SPJ1

6 0

2 years ago

Solve the equation for theta (0°≤theta<360°)<br><br>2 sin theta = 1

Oduvanchick [21]

Answer:

30 degrees

Step-by-step explanation:

To figure out theta is using a bit of simple trigonometry.

2sin(theta) = 1

= sin(theta) = 0.5

Using arcsin (sin^-1) we can isolate x

x = arcsin(0.5)

x = 30

4 0

2 years ago

Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound

cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0$

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

$p_1=X_1/n_1=188/244=0.77049$

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

$p_2=X_2/n_2=197/247=0.79757$

The difference between proportions is (p1-p2)=-0.02708.

$p_d=p_1-p_2=0.77049-0.79757=-0.02708$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76$

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=P(t$

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0

3 years ago

Salaries of 49 college graduates who took a statistics course in college have a mean, x overbar, of $ 65 comma 300. Assuming a

Molodets [167]

Answer: $60,540< \mu$