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mihalych1998 [28]

2 years ago

10

Someone please help me ! Its past due and Ive been busy.. D:

1 answer:

oee [108]2 years ago

4 0

Answer:

It's okay the first answer is right, $0.15

The store makes $4.20 off the rope

Step-by-step explanation:

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Find the sum and express it in simplest form <br> (6y-2c+2)+(-3y+4c)

Taya2010 [7]

Well, kid all you have to do is add like terms and place the subjected terms in alphabetical order.
1. (6y-2c+2)+(-3y+4c)
2. 6y + - 3y = 3y
3. -2c+4c =2c
4. the positive in the first set of parenthesis has to term other than its number by itself. (so it remains alone and only positive 2)
5. take all the separate term answers and add them into a complete expression- 3y + 2c + 2: and that is all

3 0

3 years ago

F(x) = x2 + 4x + 3 symmetry of -2

Brrunno [24]

Answer:

IDK

Step-by-step explanation:

search up yt vid or use https://www.mathpapa.com/algebra-calculator.html

7 0

2 years ago

Which ordered pair is a solution to the system of linear equations One-half x minus three-fourths y = StartFraction 11 Over 60 E

s344n2d4d5 [400]

Answer:

$\left(\dfrac{2}{3},\dfrac{1}{5}\right)$

Step-by-step explanation:

Given the system of two equations:

$\left\{\begin{array}{l}\dfrac{1}{2}x-\dfrac{3}{4}y=\dfrac{11}{60}\\ \\\dfrac{2}{5}x+\dfrac{1}{6}y=\dfrac{3}{10}\end{array}\right.$

Multiply the first equation and the second equation by 60 to get rid of fractions:

$\left\{\begin{array}{l}30x-45y=11\\ \\24x+10y=18\end{array}\right.$

Now multiply the first equation by 4 and the second equation by 5:

$\left\{\begin{array}{l}120x-180y=44\\ \\120x+50y=90\end{array}\right.$

Subtract them:

$(120x-180y)-(120x+50y)=44-90\\ \\120x-180y-120x-50y=-46\\ \\-230y=-46\\ \\y=\dfrac{46}{230}=\dfrac{1}{5}$

Substitute it into the first equation:

$30x-45\cdot \dfrac{1}{5}=11\\ \\30x-9=11\\ \\30x=11+9\\ \\30x=20\\ \\x=\dfrac{2}{3}$

The solution is $\left(\dfrac{2}{3},\dfrac{1}{5}\right)$

4 0

3 years ago

Read 2 more answers

Lorico [155]

Answer:31

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

the radius of a circle is 2 cm. A point 8cm away from the center of the circle. What is the length of the tangent drawn to the c

SIZIF [17.4K]

Answer:

7.75 cm

Step-by-step explanation:

Let a circle having centre O and AB is a tangent of the circle and OB is the radius of the circle = 2 cm. And join AO such that AO = 8 cm.

$AB=\sqrt{(AO)^{2}- (OB)^{2}} cm$

$AB=\sqrt {8^{2}-2^{2}}=\sqrt{60}=7.745966692 cm\approx 7.75 cm$

3 0

2 years ago