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3 years ago

13

Allison practices her violin for at least 12 hours per week. She practices for three fourths of an hour each session. If Allison

has already practiced 3 hours this week, how many more sessions remain for her to meet or exceed her weekly practice goal?

1 answer:

dolphi86 [110]3 years ago

8 0

Answer:

Sessions needed= 12

Step-by-step explanation:

Giving the following information:

Total hours= 12 hours

Practice= 3/4= 0.75 of an hour

Already practiced= 3 hours

<u>First, we need to determine how many minutes does she practice each session:</u>

Minutes per session= 0.75*60= 45 minutes

<u>Now, we divide the total practice in minutes required for the minutes per session:</u>

Sessions needed= (9*60) / 45

Sessions needed= 12

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Can someone please help me with this ASAP‼️ Thank You

AVprozaik [17]

Let x = cost of the dishwasher.

The amounts the children are paying are:

Mark =20% = 1/5, so 1/5x

Sorin = 75

Raymond = 1/4x

Stephanie = 75

Kristin = 1/3x

Add them together:

x = 1/5x + 1/4x + 1/3x + 75 + 75

x - ( 1/5x + 1/4x + 1/3x ) = 150

Rewrite fractions with common denominator:

x - ( 12/60x + 15/60x + 20/60x ) = 150

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x = 150/1 • 60/13

x = 9000/13

x = 692.31

The total cost of the dishwasher is $692.31

Now calculate the amount each child pays:

Mark = 1/5 x = 692.31/ 5 = $138.46

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Stephanie = $75.00

Kristin = 1/3 x = 692.31 / 3 = $230.77

5 0

3 years ago

Solve 9/10=z/8 . Round to the nearest tenth.

kompoz [17]

$\boxed {Question}$
$\frac{9}{10} = \frac{z}{8}$

$\boxed {Cross \ multiply}$
$10z = 8 \times 9$

$\boxed {Evaluate}$
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3 years ago

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Ksju [112]

Answer:

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2 years ago

A man invest 5,200,part at 4% and the balance at 3%. If his total income for the two investments is $194,how much money did he i

Fed [463]

Let the amount invested at 4% be = x

Let the amount invested at 3% be = y

Given is:

$x+y=5200$ or $x=5200-y$ .... (1)

As, total income for the two investments is $194, so equation is:

$0.04x+0.03y=194$ ....(2)

Putting value of x from (1) in (2)

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