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a_sh-v [17]
3 years ago
15

I would like to create a rectangular vegetable patch. The fencing for the east and west sides costs $4 per foot, and the fencing

for the north and south sides costs only $2 per foot. I have a budget of $176 for the project. What are the dimensions of the vegetable patch with the largest area I can enclose?
Mathematics
1 answer:
ss7ja [257]3 years ago
5 0
X = E/W dimension 
<span>y = N/S dimension </span>

<span>4x + 4x + 2y + 2y = 64 </span>
<span>8x + 4y = 64 </span>
<span>4y = 64 - 8x </span>
<span>y = 16 - 2x </span>

<span>Area = xy = x(16 - 2x) = 16x - 2x^2 </span>

<span>Maximum of y = ax^2 + bx + c is when x = -b / 2a </span>

<span>so x = -16 / -4 = 4 </span>
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A line crosses through the points (0,2) and (-10, -16) Which of the following is the slope of the line?
Elodia [21]

Answer:

  9/5

Step-by-step explanation:

The slope between the two points can be found by ...

  m = (y2 -y1)/(x2 -x1)

  m = (-16-2)/(-10-0) = -18/-10

  m = 9/5

The slope of the line is 9/5. Perhaps this is a match to choice A.

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Which ratio is equivalent to the rate<br> 8 meters<br> 1 second<br> ?
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strawberries cost $2 per pound and gets 20% discount on the total cost. How much does Kate pay for the strawberries?
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What is the best estimate for the product of 289 and 7?
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The answer to your question is 300 and 10
7 0
4 years ago
9.
viktelen [127]

Answer:

A. y = 2^x + 5

Step-by-step explanation:

The equation is not linear, so a constant slope does not exist.

Not Linear                     PARALLEL

...................................................................................................................................................

The equation is not linear, so a constant slope does not exist.

Not Linear                         PERPENDICULAR

...............................................................................................................................................

First, remember that if two lines are parallel, they have the same slope. The problem already gave us a point on the line and we now have the power to find the slope. Since we have the slope and a point on the line, we are going to find the equation of the line through the point-slope formula, which is:

 is a point on the line

is the slope of the line

The equation given to us has a slope of 2, as we can see because the line is in slope-intercept form. Also, we are given the point (3, 11), which we are told is on the line. Since we are already given all of the information for the point-slope formula, we can simply substitute it in and solve for the equation.

Set up

Use the Distributive Property on both sides

Add 11 to both sides and simplify

The equation of our line is y = 2x + 5.

...............................................................................................................................................

Slope-intercept form:

y = mx + b   "m" is the slope, "b" is the y-intercept (the y value when x = 0)

For lines to be parallel, they have to have the SAME slope.

The given line's slope is 2, so the parallel line's slope is also 2.

y = 2x + b

To find "b", plug in the point (3,11) into the equation.

y = 2x + b

11 = 2(3) + b      Multiply 2 and 3

11 = 6 + b      Subtract 6 on both sides

5 = b

y = 2x + 5

3 0
3 years ago
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