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Zigmanuir [339]
3 years ago
11

You are dealt two cards successively without replacement from a shuffled deck of 52 playing cards. Find the probability of the f

ollowing events. Express your answer as a simplified fraction. Both cards are black First card is a King and the second card is a Queen. Both cards are of a different color.
Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

13/25 -52=0.013

Step-by-step explanation:

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The graphs of the equations Ax + By =15 and Ax - By =9 intersect at (2, 1). Find A and B. Show or explain your reasoning
iVinArrow [24]
Hi here’s the answers hope this helps

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I’m not sure what the last one is .. can u help pls
Anarel [89]

Answer:

136

Step-by-step explanation:

180 - <BAC

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HR contains six red chili beans for green jellybeans and four blue jelly beans if we choose a jellybean then another jellybean w
Zigmanuir [339]
Probability first one is blue is 4/6+4+4=4/14
the second one is also blue is 4-1/6+4+4-1=3/13

The probability of getting blue both time is 4/14*3/13=12/182=0.0659=6.59%

Answer:
0.0659 or 6.59%
7 0
4 years ago
-1^{2008} + (-1)^{2007} = ?<br><br> (1 - (-1)^[11])^[2] = ?<br><br> Questions for fun~
vladimir2022 [97]
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7 0
3 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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