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Dimas [21]
3 years ago
13

Evaluate the expression a +7 when a=4, b=2, and c=8

Mathematics
2 answers:
tatyana61 [14]3 years ago
8 0

Answer:

a + 7

so "a" is 4 so

4+7=11

Hope this helps!

Alborosie3 years ago
3 0

If a=4 and the equation is a+7 then the equation would be, with the numbers plugged in, 4+7 which equals 11.

Answer: 11

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G. If two triangles have three corresponding angles and three corresponding sides that are
Alex777 [14]

Answer:

Yes.

Step-by-step explanation:

Yes they are because that is the definition of congruency.

4 0
3 years ago
A population of size 3,624 grows at a rate of 3% per year, compounded continuously. How big will the population be in 2 years?
rodikova [14]

Answer:

Step-by-step explanation:

The continuous compound formula is

y=Pe^{rt where P is the principle or starting value, r is the growth rate in decimal form, and t is the time in years. For us:

y=3624e^{(.03)(2)}\\y=3624e^{.06}\\y=3624(1.061836547)\\y=3848.09

which would probably round to just 3848 people.

8 0
3 years ago
I'm confused on #21. It's very hard. I tried starting it but I gave up.
UkoKoshka [18]
Can't read the full question
7 0
3 years ago
Read 2 more answers
Seven times a number minus the number is -48.
DENIUS [597]
Same as the other one :) if u thought my answers were helpful to you please mark me as brainliest :)

5 0
3 years ago
Read 2 more answers
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
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