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Umnica [9.8K]
3 years ago
14

Y ( y + 4) - y = 6 is a quadratic equation. True False

Mathematics
1 answer:
ratelena [41]3 years ago
5 0

Answer:

y(y+4)-y=6

y2+4y-y2

y2_y2+4y

4y=6

false

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Find the measure of angle b 59=b​
IRISSAK [1]

Answer:

A.

Step-by-step explanation:

5 0
3 years ago
Which graph represents an exponential function?
geniusboy [140]

Answer:The function that represents an exponential function is the 4th graph and it can be modeled as y = aeᵇˣ.

What are exponential functions?

The exponential functions are written in the form of y = aeᵇˣ, where the output y increases exponentially for the input x.

In order to find the graph that represents an exponential function, we will discuss each of the following graphs,

For the 1st graph, (Black),

In the first graph, the graph is of a parabola, and the function which represents this kind of graph is a quadratic equation, therefore, this graph represents a parabolic equation. It is given by the function,

y=ax²+bx+c or y=a(x-h)²+k

For the 2nd graph, (Red),

In the second graph, the graph represented is the graph of a reciprocal function, the function that can be represented by the graph,

y=a/x + b

For the 3rd graph, (Blue),

In the third graph, the graph represented is the graph of root function, it can be modeled as,

y = a+√(x+b)

For the 4th graph, (Green),

In the fourth graph, the graph represented is the graph of an exponential function, and it can be modeled as,

y = aeᵇˣ

Hence, the function that represents an exponential function is the 4th graph and it can be modeled as y = aeᵇˣ.

Step-by-step explanation:

7 0
2 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
1 year ago
Answer answer answer answer
Mice21 [21]

Answer:

12 \leqslant x < 26

4 0
3 years ago
Help please 10 points
irga5000 [103]

Answer:   it's the third one and the first one

Step-by-step explanation:

6 0
3 years ago
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